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3 years ago

Which of the following geological features can form at a subduction zone?

1 answer:

3 0

This feature is formed at destructive boundaries where the denser plate (usually the oceanic plate) is subducted underneath the less dense plate (usually the continental plate).

Explanation:

the stress in the boundary between the two plates causes them to warp at the boundary forming a trench. This forced bending and the friction between the two plates (remember tectonic plates are very rugged) causes fissures to develop at the boundary. As the denser plate dives into the mantle, it begins to melt and the molten rock rises through the fissures. The magma erupts at the surface in several fissures forming volcanic mountains ranges along the convergent boundary.

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About how much evaporation in the water cycle occurs over the ocean?

ioda

Easy it’s 86 so the third option

5 0

2 years ago

How many moles of a gas would occupy 22.4 Liters at 273 K and 1 atm?

Molodets [167]

Answer:

1 mole of a gas would occupy 22.4 Liters at 273 K and 1 atm

Explanation:

An ideal gas is a set of atoms or molecules that move freely without interactions. The pressure exerted by the gas is due to the collisions of the molecules with the walls of the container. The ideal gas behavior is at low pressures, that is, at the limit of zero density. At high pressures the molecules interact and intermolecular forces cause the gas to deviate from ideality.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case:

P= 1 atm
V= 22.4 L
n= ?
R= 0.082 $\frac{atm*L}{mol*K}$
T=273 K

Reemplacing:

1 atm* 22.4 L= n* 0.082 $\frac{atm*L}{mol*K}$ *273 K

Solving:

$n=\frac{1 atm* 22.4 L}{0.082 \frac{atm*L}{mol*K} *273 K}$

n= 1 mol

Another way to get the same result is by taking the STP conditions into account.

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C (or 273 K) are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

1 mole of a gas would occupy 22.4 Liters at 273 K and 1 atm

4 0

2 years ago

Predict the products of below reaction, and whether the solution at equilibrium will be acidic, basic, or neutral.

kati45 [8]

Answer: The product of the given reaction is $HNO_{3}$ and the solution at equilibrium will be acidic.

Explanation:

When two or more chemical substances react together then it forms new substances and these new substances are called products.

For example, $3N_{2}O_{5} + 3H_{2}O \rightarrow 6HNO_{3}$

This shows that nitric acid $(HNO_{3})$ is the product formed and it is an acidic substance.

Hence, the solution at equilibrium will be acidic in nature.

Thus, we can conclude that the product of the given reaction is $HNO_{3}$ and the solution at equilibrium will be acidic.

8 0

3 years ago

The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when

tia_tia [17]

Answer : The cell potential for this reaction is 0.50 V

Explanation :

The given cell reactions is:

$Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)$

The half-cell reactions are:

Oxidation half reaction (anode): $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction (cathode): $Pb^{2+}+2e^-\rightarrow Pb$

First we have to calculate the cell potential for this reaction.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}$

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = $25^oC=273+25=298K$

n = number of electrons in oxidation-reduction reaction = 2

$E^o_{cell}$ = standard electrode potential of the cell = +0.63 V

$E_{cell}$ = cell potential for the reaction = ?

$[Zn^{2+}]$ = 3.5 M

$[Pb^{2+}]$ = $2.0\times 10^{-4}M$

Now put all the given values in the above equation, we get:

$E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}$

$E_{cell}=0.50V$

Therefore, the cell potential for this reaction is 0.50 V

5 0

3 years ago

A slice of pizza has 500 kcal. If we could burn the pizza and use all the heat to warm a 50-L container of cold water, what woul

gayaneshka [121]

Answer:

10°C

Explanation:

Heat gain by water = Heat lost by the slice of pizza

Thus,

$m_{water}\times C_{water}\times \Delta T=Q$

For water:

Volume = 50.0 L

Density of water= 1 kg/L

So, mass of the water:

$Mass\ of\ water=Density \times {Volume\ of\ water}$

$Mass\ of\ water=1 kg/L \times {50.0\ L}$

Mass of water = 50 kg

Specific heat of water = 1 kcal/kg°C

ΔT = ?

For slice of pizza:

Q = 500 kcal

So,

$50\times 1\times \Delta T=500$

ΔT = 10°C

Increase in temperature = 10°C

3 0

2 years ago