Answer:
Therefore, the force supported by the hydraulic cylinder is = -70.01 lb
Thus, the force supported by the bar = -233.84 lb
The reaction force supported by the reaction of the roller = 341.31 lb
Explanation:
The attached diagrams is shown in the file below:
From there; taking moments about point A
- 40 (180) - (80) Cos 37° + 55
-7200 + (-80 Cos 37° + 55 sin 37° ) = 0
= - 7200 - 30.79
- 30.79 = 7200
=
= -233.84 lb
Thus, the force supported by the bar = -233.84 lb
Taking the equilibrium of forces in the vertical direction
sin 37 +
cos 20 -
= 0
- 233.84 sin 37 + cos 20 - 180 = 0
cos 20 = 320.73
=
= 341.31 lb
The reaction force supported by the reaction of the roller = 341.31 lb
Taking the equilibrium of forces on the horizontal direction.
cos 37 -
sin 20° = 0
-233.84 cos 37 - + 341.31 sin 20° = 0
-186.75 - + 116.74 = 0
- -70.01 = 0
- = 70.01
= - 70.01 lb
Therefore, the force supported by the hydraulic cylinder is = -70.01 lb
