Answer:
5.55 L
Explanation:
This excersise can be solved by the Boyle's law.
This law for gases states that the pressure of a gas in a vessel is inversely proportional to the volume of the vessel.
P₁ . V₁ = P₂ . V₂
The law comes from the Ideal Gases Law, in the first term.
P . V = n . R . T In this case, n . R . T are all constant.
6.35 L . 88.6 kPa = 101.3 kPa . V₂
V₂ = (6.35 L . 88.6 kPa) / 101.3 kPa
V₂ = 5.55 L
It is inversely proportional because, as it happened in this case, pressure was increased, therefore volume decreased.
Answer:
See explanation
Explanation:
Before the advent of the wave-particle duality theory proposed by Louis de Broglie, there was a sharp distinction between mater and waves.
However, Louis de Broglie introduced the idea that mater could display wave-like properties. Erwin Schrödinger developed this idea into what is now known as the wave mechanical model of the atom.
In this model, electrons are regarded as waves. We can only determine the probability of finding the electron within certain high probability regions within the atom called orbitals.
This idea has been the longest surviving atomic model and has greatly increased our understanding of atoms.
When the reaction equation is:
CaSO3(s) → CaO(s) + SO2(g)
we can see that the molar ratio between CaSO3 & SO2 is 1:1 so, we need to find first the moles SO2.
to get the moles of SO2 we are going to use the ideal gas equation:
PV = nRT
when P is the pressure = 1.1 atm
and V is the volume = 14.5 L
n is the moles' number (which we need to calculate)
R ideal gas constant = 0.0821
and T is the temperature in Kelvin = 12.5 + 273 = 285.5 K
so, by substitution:
1.1 * 14.5 L = n * 0.0821 * 285.5
∴ n = 1.1 * 14.5 / (0.0821*285.5)
= 0.68 moles SO2
∴ moles CaSO3 = 0.68 moles
so we can easily get the mass of CaSO3:
when mass = moles * molar mass
and we know that the molar mass of CaSO3= 40 + 32 + 16 * 3 = 120 g/mol
∴ mass = 0.68 moles* 120 g/mol = 81.6 g
The element has 83 electrons
