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3 years ago

What is a good concluding thought about what happens to your body if you drink a Coke

1 answer:

7 0

Your fluid intake is enhanced, you feel refreshed, you get a sugar high for a while, and a lot if the rust is removed from your stomach and small intestine.

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Coral reefs reduce the amount of carbon dioxide in the oceans. People have destroyed many natural coral reefs through pollution.

Mariulka [41]

The Answer is A!

Hope this helps :)

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4 years ago

PLeAsE hElp What is the kinetic energy of 14 Kg traveling at a velocity of 3m/s east

harkovskaia [24]

Answer:

Please see the given attachment.

Explanation:

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4 0

3 years ago

What is Newton first law?

Anit [1.1K]

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force

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3 years ago

We can reasonably model a 90-W incandescent lightbulb as a sphere 5.7 cm in diameter. Typically, only about 5% of the energy goe

o-na [289]

Answer:

See answer

Explanation:

Given quantities:

$\eta = 0.05\\ W=90[W]\\r=0.0285[m]$

where $\eta$ is the efficiency of the lightbulb (visible light is 5% of the total power), $W$ is the total power of the lightbulb, r is the radius of the lightbulb in meters.

Intensity is power divided by area:

$I =\frac{P}{A}$

a) Now the effective power is $\eta*W$ , therefore:

$I =\frac{\eta*W}{\pi r^2}=\frac{0.05*90}{4\pi (0.0285)^2}=440.87[W/m^2]$

b) Now the intensity is the average poynting vector is related to the magnitudes of the maximum electric field and magnetic field amplitudes, following:

$S_{average}= \frac{EB}{2\mu_{0}}[W/m]$

now $E$ and $B$ are related:

$E=cB\\ B=\frac{E}{c}$ and $c=\frac{1}{\sqrt{\epsilon_{0} \mu_{0}}}$

replace in $S_{average}$

$S_{average}=I= \frac{c \epsilon_{0}E^2}{2}[W/m]$

we replace the values and we get:

$E= \sqrt{\frac{2I}{\epsilon_{0}c}}$

$E = \sqrt{\frac{2(440.8)}{8.85*10^{-12}3*10^8}}=576.24[V/m]$

therefore

$B=\frac{E}{c}=\frac{576.24}{3*10^{8}}=1.92*10^{-6}[T]$

8 0

4 years ago

A hotdog cannon shoots a hotdog straight up in the air with an initial velocity of 30 m/s. How high will the hotdog fly?

Yuri [45]

At its peak height, the hotdog will have no vertical velocity, so that

${v_f}^2-{v_i}^2=2(-g)\Delta y\implies-\left(30\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}$

$\implies y_{\mathrm{max}}=46\,\mathrm m$

7 0

3 years ago