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3 years ago

What is the pH of a sample with [OH-] = 2.5 x 10-11 M?

Chemistry

1 answer:

sveticcg [70]3 years ago

3 0

Answer:

The pH of the sample is 3,4.

Explanation:

We calculate the pOH from the formula pOH = -log (OH-). We know that for all aqueous solutions: pH + pOH = 14, and from there we clear pH:

pOH= -log (OH-)=10,60

pH + pOH = 14

pH + 10,60 = 14

pH=14 -10,60

pH=3,4

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A substance registers a temperature change from 20 to 40 to what incremental temperature change does this correspond

ss7ja [257]

Given:

Initial temperature, T1 = 20 C

Final temperature, T2 = 40 C

To determine:

The temperature change

Explanation:

Convert degree C to Kelvin

Temperature in Kelvin = degree C + 273

T1 = 20 + 273 = 293 K

T2 = 40 + 273 = 313 K

Incremental temperature change = T2 - T1 = 313-293 = 20 K

Ans: The temperature change in kelvin is 20 K

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pishuonlain [190]

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fenix001 [56]

Answer:

$r_{H_2} = \frac{-1}{2} r_{HI}$

Explanation:

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