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Eduardwww [97]
2 years ago
14

Can somebody help me please

Chemistry
1 answer:
djverab [1.8K]2 years ago
5 0

Answer:

匿名のハック

Explana

あなたはオタクになります

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How many milliliters of 0.200 m fecl3 are needed to react with an excess of na2s to produce 1.38 g of fe2s3 if the percent yield
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<span>Answer: 100 ml
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<span>Explanation:


1) Convert 1.38 g of Fe₂S₃ into number of moles, n


</span>i) Formula: n = mass in grass / molar mass
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ii) molar mass of </span><span>Fe₂S₃ =2 x 55.8 g/mol + 3 x 32.1 g/mol = 207.9 g/mol
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<span>65% = 0.65 = actual yield/ theoretical yield =>


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<span> 3 Na₂S(aq) + 2 FeCl₃(aq) → Fe₂S₃(s) + 6 NaCl(aq)


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