Let's start with the amount given in percent. Let our basis be 100 grams of compound. So, that means that in this amount, 57.1 g is oxygen and 100-57.1=42.9 g is carbon. Since there is 1:1 atom ratio, it also means that moles oxygen = moles carbon.
Moles = Mass/Relative Mass Let x be the relative mass of oxygen
57.1/16 = 42.9/x Solving for x, <em>x = 12.02 amu</em>
