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mezya [45]
3 years ago
8

What is the moden periodic law​

Chemistry
1 answer:
Zarrin [17]3 years ago
5 0

Answer:

Here's what I get  

Explanation:

The modern periodic law states that the physical and chemical properties of the elements are periodic functions of their atomic numbers.

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In 25 words or fewer, what do you think a scientist would want to explain about this soda?
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Answer:

This soda is brown, sweet, has high carbonation, and is about 200 calories when consumed.

Explanation:

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2 years ago
How many grams of CrSO3 are in 2.4 moles of CrSO3
castortr0y [4]

Answer: 316.8 g CrSO3

Explanation: Solution:

2.4 moles CrSO3 x 132 g CrSO3 / 1 mole CrSO3 = 316.8 g CrSO4

The conversion factor is 1 mole of CrSO4 is equal to its molar mass which is 132 g CrSO3

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2 years ago
A 6-column table with 2 rows. The first column labeled number of washers has entries 1, 2. The second column labeled initial vel
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Answer:

A) The acceleration due to gravity for any object, including 1 washer on the string, is always assumed to be  10  m/s2.

B) The mass of 3 washers, when converted to kg, is  0.0147  kg.

C) The applied force of 3 washers will increase the applied force on the car to 0.147 N.

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8 0
3 years ago
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Arrange these steps related to climate change in the correct order.
Eva8 [605]
4, 2, 1, and 3 is the answer
5 0
3 years ago
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El agua del mar contiene aproximadamente un 3,0 % m/v de sal (NaCl, 58,44 g/mol), (asuma que es la única fuente de cloruros) si
Alchen [17]

Answer:

s = 4.41 g/L.

Explanation:

¡Hola!

En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:

PbCl_2(s)\rightleftharpoons 2Cl^-(aq)+Pb^{2+}(aq)

Lo cual hace que la expresión de equilibrio se calcule como:

Ksp=[Pb^{2+}][Cl^-]^2

Y que en términos de la solubilidad molar, s, se resuelve como:

1.6x10^{-5}=s(2s)^2\\\\1.6x10^{-5}=4s^3\\\\s=\sqrt[3]{\frac{1.6x10^{-5}}{4} } \\\\s=0.0159molPbCl_2/L

Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):

s=0.0159molPbCl_2/L*\frac{278.1gmolPbCl_2}{1molmolPbCl_2} \\\\s=4.41g/L

¡Saludos!

7 0
2 years ago
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