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I am Lyosha [343]
3 years ago
11

A certain weak acid, ha, has a ka value of 6.0×10−7. calculate the percent ionization of ha in a 0.10 m solution.

Chemistry
1 answer:
joja [24]3 years ago
5 0
For the purpose, we will use the equation for determining the dissociation constant from concentration and <span>percent of ionization:

Kd = c </span>× α²

α = √(Kd/c) × 100%

Kd = 6.0×10⁻⁷

c(HA) = 0.1M

α = √(6.0×10⁻⁷/0.1)  × 100% =  0.23%

So, in the solution, the acid <span>percent of ionization will be just 0.23%.</span>

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WILL GIVE YOU BRAINLIEST!!!
Papessa [141]

Answer:

A ability to decompose

B reactivity

Explanation:

Chemical properties are those properties that tell us about what a substance can do as regards to whether or not the substance reacts with other substances.

Examples are flammability, rusting of iron, precipitation, decomposition of water by an electric current.

The ability to decompose and reactivity are chemical properties of a substance.

  • Physical properties tells us everything about what a substance is when no change is occurring to its constituents.
  • Examples are state of matter, color, odor, taste, texture, hardness e.t.c

5 0
3 years ago
Read 2 more answers
At 20 ∘C the vapor pressure of benzene C6H6 is 75 torr and that of toluene C7H8 is 22 torr. Assume that benzene and toluene fo
Olegator [25]

Answer:

a) Xbenzene = 0.283

b) Xtoluene = 0.717

Explanation:

At T = 20°C:

⇒ vapor pressure of benzene (P*b) = 75 torr

⇒ vapor pressure toluene (P*t) = 22 torr

Raoult's law:

  • Pi = Xi.P*i

∴ Pi: partial pressure of i

∴ Xi: mole fraction

∴ P*i: vapor pressure at T

a) solution: benzene (b) + toluene (t)

∴ Psln = 37 torr;   at T=20°C

⇒ Psln = Pb + Pt

∴ Pb = (Xb)*(P*b)

∴ Pt = (Xt)*(P*t)

∴ Xb + Xt = 1

⇒ Psln = 37 torr = (Xb)(75 torr) + (1 - Xb)(22 torr)

⇒ 37 torr - 22 torr = (75 torr)Xb - (22 torr)Xb

⇒ 15 torr = 53 torrXb

⇒ Xb = 15 torr / 53 torr

⇒ Xb = 0.283

b) Xb + Xt = 1

⇒ Xt = 1 - Xb

⇒ Xt = 1 - 0.283

⇒ Xt = 0.717

6 0
4 years ago
Calculate the molarity of a solution of Nach if it contains 7.2.g Nach in 100.0 mL of solution. andver: m Nach . .
Norma-Jean [14]

Answer:

1.23 M

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity  

V = volume of solution in liter ,

n = moles of solute ,

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,  

n = w / m

n = moles ,  

w = given mass ,  

m = molecular mass .

From the question ,

w = given mass of NaCl = 7.2 g

As we know , the molecular mass of NaCl = 58.5 g/mol

Moles is calculated as -

n = w / m  =  7.2 g / 58.5 g/mol = 0.123 mol

Molarity is calculated as -

V = 100ml = 0.1 L            (since , 1 ml = 1/1000L )

M = n / V  =  0.123 mol / 0.1 L = 1.23 M

5 0
3 years ago
A piece of silver releases 202.8 J of heat while cooling 65.0 °C. What is the mass of the sample? Silver has a specific heat of
KiRa [710]

Answer: 13 grams

Explanation:

The quantity of heat energy (Q) released from a heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 202.8 Joules

Mass of silver = ?

C = 0.240 J/g °C.

Φ = 65°C

Then, Q = MCΦ

202.8J = M x 0.240 J/g °C x 65°C

202.8J = M x 15.6 J/g

M = (202.8J / 15.6 J/g)

M = 13 g

Thus, the mass of silver is 13 grams

7 0
3 years ago
A solution of permanganate is standardized by titration with oxalic acid, . To react completely with mol of oxalic acid required
Zielflug [23.3K]

Answer:

M=0.120M

Explanation:

Hello,

In this case, the undergone chemical reaction is:

MnO_4^-(aq)+H_2C_2O_4(aq)\rightarrow Mn^{+2}+CO_2

In such a way, the acidic redox balance turns out:

(Mn^{+7}O_4)^-+5e^-+8H^+\rightarrow Mn^{+2}+4H_2O\\H_2C_2O_4\rightarrow2CO_2+2H^++2e^-

Which leads to the total balanced equation as follows:

2(MnO_4)^-(aq)+6H^+(aq)+5H_2C_2O_4(aq)\rightarrow2Mn^{+2}(aq)+8H_2O(l)+10CO_2(g)

Thus, as the mass of oxalic acid is not given, one could suppose a value of 1 g (which you can modify based on the actual statement) in order to compute the oxalic acid moles as shwon below:

1gH_2C_2O_4*\frac{1molH_2C_2O_4}{90.04gH_2C_2O_4} *\frac{2mol(MnO_4)^-}{5molH_2C_2O_4} =0.00444mol(MnO_4)^-

Whereby the molality results:

M=\frac{0.00444mol(MnO_4)^-}{0.03702L} =0.120M

Remember you can modify the oxalic acid mass as you desire.

Best regards.

5 0
4 years ago
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