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I am Lyosha [343]
3 years ago
11

A certain weak acid, ha, has a ka value of 6.0×10−7. calculate the percent ionization of ha in a 0.10 m solution.

Chemistry
1 answer:
joja [24]3 years ago
5 0
For the purpose, we will use the equation for determining the dissociation constant from concentration and <span>percent of ionization:

Kd = c </span>× α²

α = √(Kd/c) × 100%

Kd = 6.0×10⁻⁷

c(HA) = 0.1M

α = √(6.0×10⁻⁷/0.1)  × 100% =  0.23%

So, in the solution, the acid <span>percent of ionization will be just 0.23%.</span>

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A rectangle box measures 6.00 in. in length, 7.00 in. in width, and 8.00 in. in height. The volume of the rectangular box is 5.506 L

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Learn more about Volume of rectangular brainly.com/question/21308574

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