The table below shows the number of sub-atomic particles in an atom of magnesium.

love history [14]

It is each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and hence differ in relative atomic mass but not in chemical properties; in particular, a radioactive form of an element.

7 0

3 years ago

Liquid octane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 10.3 g of octane is m

dsp73

Answer:

$\large \boxed{\text{31.8 g CO}_{2}}$

Explanation:

We are given the masses of two reactants and asked to determine the mass of the product.

This looks like a limiting reactant problem.

1. Assemble the information

We will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.

MM: 114.23 32.00 44.01

2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 18H₂O

Mass/g: 10.3 69.

2. Calculate the moles of each reactant

$\text{Moles of C$_{8}$H$_{18}$} = \text{10.3 g C$_{8}$H$_{18}$} \times \dfrac{\text{1 mol C$_{8}$H$_{18}$}}{\text{114.23 mol C$_{8}$H$_{18}$}} = \text{0.090 17 mol C$_{8}$H$_{18}$}\\\\\text{Moles of O$_{2}$} = \text{69. g O}_{2} \times \dfrac{\text{1 mol O$_{2}$}}{\text{32.00 g O$_{2}$}} = \text{2.16 mol O$_{2}$}$

3. Calculate the moles of CO₂ from each reactant

$\textbf{From C$_{8}$H$_{18}$:}\\\text{Moles of CO$_{2}$} = \text{0.090 17 mol C$_{8}$H$_{18}$} \times \dfrac{\text{16 mol CO$_{2}$}}{\text{2 mol C$_{8}$H$_{18}$}} = \text{0.7214 mol CO}_{2}\\\\\textbf{From O$_{2}$:}\\\text{Moles of CO$_{2}$} =\text{2.16 molO$_{2}$} \times \dfrac{\text{16 mol CO$_{2}$}}{\text{25 mol O$_{2}$}} = \text{1.38 mol CO$_{2}$}\\\\\text{Octane is the limiting reactant because it gives fewer moles of CO$_{2}$.}$

4. Calculate the mass of CO₂

$\text{ Mass of CO$_{2}$} = \text{0.7214 mol CO$_{2}$} \times \dfrac{\text{44.01 g CO$_{2}$}}{\text{1 mol CO$_{2}$}} = \textbf{31.8 g CO}_\mathbf{{2}}\\\\\text{The reaction produces $\large \boxed{\textbf{31.8 g CO}_\mathbf{{2}}}$}$

5 0

3 years ago

PLEASE ANSWER ASAP!!

Advocard [28]

Answer:

the picture above should help you

5 0

2 years ago

What is the classification of a solution of naoh with a ph of 8.3?

Maksim231197 [3]

Answer:

<u>Alkaline or basic solution </u>(alkaline and basic means the same)

Explanation:

According to the <em>pH</em>, solutions may be classified as neutral, acidic, or alkaline (basic).

This table shows such classification:

pH classification

7 neutral

> 7 alkaline or basic

< 7 acidic

Thus, since the pH of the solution is 8.3, which is greater than 7, the solution is classified as basic (alkaline).

Additionally, you must learn that pH is a logarithmic scale for the concentration of hydronium ions in the solution.

pH = - log [H₃O⁺]

You can calculate the concentration of hydronium ions using antilogarithm properties:

$pH=-log[H_3O^+]\\ \\ {[H_3O^+]}=10^{-pH}\\ \\ {[H_3O^+]}=10^{-8.3}=0.00000000501$

NaOH solutions are alkaline solutions, bases, according to Arrhenius model, because they contain OH⁻ ions and release them when ionize in water.

8 0

3 years ago

Calculate the value of the equilibrium constant, Kc, for the reaction below, if 0.208 moles of sulfur dioxide gas, 0.208 moles o

Harman [31]

First, we convert the moles of each substance into the concentration using the volume of the reactor.
[SO₃] = 0.425/1.5 = 0.283 M
[SO₂] = 0.208 / 1.5 = 0.139 M
[O₂] = 0.208/1.5 = 0.139 M
The equilibrium constant is calculated by:
Kc = [SO₃]² / [O₂][SO₂]²
Kc = (0.283)²/(0.139)(0.139)²
Kc = 29.8 = 2.98 x 10¹

The answer is C

8 0

3 years ago