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3 years ago

Which fossil fuel accounts for 95% of consumption for transportation?

Chemistry

1 answer:

Ilia_Sergeevich [38]3 years ago

3 0

Answer:

oil

Explanation:

i hope this helps :)

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_AgNO3 + _ Cu → _ Cu(NO3)2 + - Ag

GuDViN [60]

Answer:

2AgNO3 + Cu = Cu(NO3)2 + 2Ag

Explanation:

First you see which side has the most elements. Which is Cu(NO3)2 + Ag. But, both sides have the same elements? But, on the reactants side, there is 2 of NO3. On the products side there is only one.

Reactants: Products:

Cu = 1 Cu = 1

NO3 = 1 NO3 = 2

Ag = 1 Ag = 1

They are all equal, except for NO3. So on the reactants side, you add a two to make it even.

2AgNO3 + Cu = Cu(NO3)2 + Ag

Reactants: Products:

Cu = 1 Cu = 1

NO3 = 2 NO3 = 2

Ag = 2 Ag = 1

Now, the NO3 is equal, But the Ag isn't. But, you can add a 2 on the products side so the whole equation becomes equal.

2AgNO3 + Cu = Cu(NO3)2 + 2Ag

Reactants: Products:

Cu = 1 Cu = 1

NO3 = 2 NO3 = 2

Ag = 2 Ag = 2

6 0

3 years ago

Two processes are described below:

Brilliant_brown [7]

B. both are chemical

5 0

3 years ago

What is the mass of oxygen in 10.0 grams of water

Inessa05 [86]

Answer:

16.00 amu

Explanation:

7 0

3 years ago

Read 2 more answers

A gas has a volume of 590ml at a tempature of -55.0 Celsius. What volume will the gas occupy at 30.0 Celsius? Show your work

Nana76 [90]

It will equal to 1,532ml

7 0

3 years ago

a laboratory procedure calls for making 510.0 mL of a 1.6 M KNO3 solution. How much KNO3 in grams is needed

barxatty [35]

Answer:

82.416 g of KNO ₃ is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.

Explanation:

Since molarity is the number of moles of solute that are dissolved in a given volume, calculated by dividing the moles of solute by the volume of the solution, the following rule of three can be applied: if in 1 L (1,000 mL) of KNO₃ there are 1.6 moles of the compound present, in 510 mL how many moles will there be?

$moles=\frac{510 mL*1.6 moles}{1000 mL}$

moles= 0.816

Being the molar mass of the elements:

K: 39 g/mole
N: 14 g/mole
O: 16 g/mole

So the molar mass of the compound KNO₃ is:

KNO₃= 39 g/mole + 14 g/mole + 3*16 g/mole= 101 g/mole

Now I can apply the following rule of three: if in 1 mole of KNO₃ there are 101 g, in 0.816 moles how much mass is there?

$mass=\frac{0.816 moles*101 grams}{1 mole}$

mass= 82.416 grams

82.416 g of KNO ₃ is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.

4 0

3 years ago