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hodyreva [135]
4 years ago
11

What is an H-R diagram

Physics
2 answers:
MArishka [77]4 years ago
6 0
Is a graphical tool that astronomers use to classify stars according to their luminosity,spectral type,color ,temperature,and evolutionary stage.
Yuliya22 [10]4 years ago
4 0

An H-R diagram is a graph that compares the relationship between a star's absolute magnitude and surface temperature.

It is a tool that is still used today to study the life cycle of stars, how stars are classified by temperature and magnitude, and how stars evolve over time.

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An automobile traveling 71.0 km/h has tires of 60.0 cm diameter. (a) What is the angular speed of the tires about their axles? (
Andrei [34K]

Explanation:

We have,

Initial speed of an automobile, u = 71 km/h = 19.72 m/s

Diameter of the tie, d = 60 cm

Radius, r = 30 cm

(a) The angular speed of the tires about their axles is given by :

\omega=\dfrac{v}{r}\\\\\omega=\dfrac{19.72}{0.3}\\\\\omega=65.73\ rad/s

(b) Final angular velocity of the wheel is equal to 0 as its stops. The angular acceleration of the wheel is given by :

\omega_f^2-\omega_i^2=2\alpha \theta

\theta=40\ rev\\\\\theta=251.32\ rad

0-\omega_i^2=2\alpha \theta\\\\\alpha =\dfrac{\omega_i^2}{2\theta}\\\\\alpha =\dfrac{(65.73)^2}{2\times 251.32}\\\\\alpha =-8.59\ rad/s^2

(c) Let the car move a distance d during the braking. So,

d=\theta r\\\\d=251.32\times 0.3\\\\d=75.39\ m

Therefore, the above is the required explanation.

7 0
4 years ago
An individual has a weight of 735 Newton’s. What is the individual’s mass? Show the appropriate equation and show your work
gogolik [260]

Explanation:

W=m*g

735=m*9.8

m=735/9.8

m=75kg

HOPE IT HELPS U!!!

5 0
3 years ago
Read 2 more answers
Titanium's specific heat capacity is 0. 523 j/g*k. how many joules of heat are required to raise the temperature of 2. 50g of ti
ad-work [718]

The amount of heat required to raise the temperature is 706.05J.

To find the answer, we need to know more about the specific heat capacity.

<h3>How to find the heat required to raise the temperature?</h3>
  • Specific heat can be defined as, the amount of heat needed to increase a substance's temperature by one degree for every gram.
  • We have the expression for amount of heat required to raise the temperature from T1 to T2 as,

                                 Q=msΔT

  • We have given with the following values,

                 m=2.50g=2.50*10^{-3}kg\\s=0.523 J/gK=\frac{0.523}{10^{-3}} J/kgK=523J/kgK\\T_1=65^0C=338K\\T_2=600^0C=873K\\

  • Thus, the amount of heat required to raise the temperature is,

            Q=2.5*10^{-3}*523*(873-333)=706.05 J

Thus, we can conclude that, the amount of heat required to raise the temperature is 706.05J.

Learn more about the specific heat capacity here:

brainly.com/question/18798150

#SPJ4

7 0
2 years ago
An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only
Pavel [41]

Answer:

vb = 22.13 m/s

Explanation:

ma = 124 kg

mb = 13 kg

vi = 2.10 m/s

According to the property of conservation of momentum, and considering that, initially, both the astronaut and the bag moved together at 2.10 m/s:

(m_a+m_b)v_i=m_av_a+m_bv_b

The minimum final velocity of the bag, vb, the will keep the astronaut from drifting away forever occurs when va = 0:

(124+13)2.10=124*0+13v_b\\v_b=\frac{287.7}{13}\\v_b= 22.13\ m/s

The minimum final velocity of the bag is 22.13 m/s.

4 0
3 years ago
A 47-kg packing crate is pulled with constant speed across a rough floor with a rope that is at an angle of 37 degrees above the
levacccp [35]

Tension in the rope due to applied force will be given as

F = 142 N

angle of applied force with horizontal is 37 degree

displacement along the floor = 6.1 m

so here we can use the formula of work done

W = F d cos\theta

now we can plug in all values above

W = 142 * 6.1 * cos37

W = 691.8 J

So here work done to pull is given by 691.8 J


8 0
3 years ago
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