Using a graphical tool to obtain the form of the wave we can see that
It is periodic in X with period = 5 cm
It is periodic in t with period = 1/125 s = 8 ms
Option B is the correct answer.
In a basketball game, a player shoots a jump shot then the floor pushes up on the player.
<h3>Newton's Third Law</h3>
Newton's third law states that when two bodies interact with each other, they apply forces to one another that are equal in magnitude and opposite in direction. The third law is also known as the law of action and reaction.
In the given situation, a player shoots a jump shot. It means that the player pushes the floor downward direction.
Newton's third law is applicable in this situation where the player pushes the floor downward direction, at the same time the floor pushes the player upward. The amount of force applied to the floor by the player is equal in magnitude and opposite in direction as compared to the force applied to the player by the floor.
Hence the option B is the correct answer.
To know more about Newton's third law, follow the link given below.
brainly.com/question/974124.
Answer:
Answered
Explanation:
v= 1 m/s
A= 1 m^2
m= 100 kg
y= 1 mm
μ = ?
ζ= viscosity of SAE 20 crankcase oil of 15° C= 0.3075 N sec/m^2
forces acting on the block are
F_s ← ↓ →F_f
mg
N= mg
F_s= shear force = ζAv/y F_f= friction force = μN
now in x- direction F_s= F_f
ζAv/y = μN
0.3075×1×1×1/1×10^{-3} = μ×100
⇒μ=0.313 (coefficient of sliding friction for the block)
Now, as the velocity is increased shear force also increases and due to this frictional force also increases.
Now, to compensate this frictional force friction coefficient must increase
as v∝μ
Answer:
The total electric flux through the shell = 34804 N.m²/C
Explanation:
φ = E.A ........................... Equation 1
Where φ = total electric flux through the shell, E = Electric Field, A = surface Area of the sphere
But,
A = 4πr² ................................... Equation 2
Where r = radius of the sphere.
Given: r = 1.4 m,
constant: π = 3.143
Substituting these values into equation 2,
A = 3.143(1.4)²
A = 6.16 m²
Also Given: E = 5650 N/C,
Substituting into equation 1,
φ = 5650(6.16)
φ = 34804 N.m²/C
Thus the total electric flux through the shell = 34804 N.m²/C