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tigry1 [53]
3 years ago
13

I NEED HELP??!!

Physics
1 answer:
user100 [1]3 years ago
4 0

The material that transmits most light is d) clear glass.

Explanation:

Depending on whether objects can transmit light or not, they can be classified into three types:

  • Opaque: an object opaque does not transmit light at all (light cannot pass through an opaque object). Examples of opaque objects are metals
  • Translucent: translucent objects allow light to pass partially through them. Examples of translucent objects are fluids
  • Transparent: transparent objects allow light to pass through them. An example of transparent objects is clear glass

In this problem, we have the following objects:

  • Umbrella: it is opaque, light does not pass through it
  • Blanket: it is opaque, light does not pass through it
  • Mirror: It is opaque, since it reflects light (light does not pass through it)
  • Clear glass: it is a transparent object

Therefore, the material that transmits most light is d) clear glass.

Learn more about light:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

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. A 40.0-kg child standing on a frozen pond throws a 0.500-kg stone to the east with a speed of 5.00 m/s. Neglecting friction be
tamaranim1 [39]

Answer:

Explanation:

A 40kg child throw stone of 0.5kg

At a direction of 5m/s

Recoil can be calculated using recoil of a gun formula

m_1•v_1 + m_2•v_2

m_1•v_1 = -m_2•v_2

The negative sign show that the momentum of the boy is directed oppositely to that of the stone

m_1 Is mass of boy

v_1 is the recoil velocity of the boy

m_2 is mass of stone

v_2 is the velocity of stone

Then,

m_1•v_1 = -m_2•v_2

40•v_1 = -0.5 × 5

40•v_1 = -2.5

v_1 = -2.5 / 40

v_1 = -0.0625 m/s

The recoil velocity of the boy is 0.0625 m/s

6 0
3 years ago
Nora walks down a street and sees a ball dropped from a building
Grace [21]
It is gravity¿ what is the question?
5 0
3 years ago
One billiard ball is shot east at 2.00 m/s. A second, identical billiard ball is shot west at 1.00 m/s. The balls have a glancin
dimulka [17.4K]

Answer:

Velocity is 1.73 m/s along 54.65° south of east.

Explanation:

Let unknown velocity be v, mass of billiard ball be m and east direction be positive x axis.

Here momentum is conserved.

Initial momentum = Final momentum

Initial momentum = m x 2i + m x (-1)i = m i

Final momentum = m x v + m x 1.41 j = mv + 1.41 m j

Comparing

mi = mv + 1.41 m j

v = i - 1.41 j

Magnitude of velocity

      v=\sqrt{1^2+(-1.41)^2}=1.73m/s        

Direction,  

       \theta =tan^{-1}\left ( \frac{-1.41}{1}\right )=-54.65^0             

Velocity is 1.73 m/s along 54.65° south of east.

5 0
3 years ago
Earth's subsystems are the geosphere, atmosphere, hydrosphere, and biosphere. Energy and matter are transferred when Earth's sub
Leona [35]

Answer:

ok

Explanation:

The Earth is made of several subsystems or "spheres" that interact to form a complex and continuously changing whole called the Earth system. Scale

Processes operating in the Earth system take place on spatial scales varying from fractions of millimeters to thousands of kilometers, and on time scales that range from milliseconds to billions of years.

Examples of instantaneous - breathing; rotation of the Earth; earthquake

Examples of long term - making coal; plate tectonics

Cycles

The Earth system is characterized by numerous overlapping cycles in which matter is recycled over and over again. Cycles involve multiple spheres and systems interactions.

Examples of cycles: day and night; rock cycle; seasons

Energy

The Earth system is powered by energy from two major sources: the Sun and the planet's internal heat.

Humans and the Earth System

People are part of the Earth system and they impact and are impacted by its materials and processes.

6 0
2 years ago
A projectile is launched straight up from a height of 960 feet with an initial velocity of 64 ft/sec. Its height at time t is h(
Natasha2012 [34]

Answer:

a) t=2s

b) h_{max}=1024ft

c) v_{y}=-256ft/s

Explanation:

From the exercise we know the initial velocity of the projectile and its initial height

v_{y}=64ft/s\\h_{o}=960ft\\g=-32ft/s^2

To find what time does it take to reach maximum height we need to find how high will it go

b) We can calculate its initial height using the following formula

Knowing that its velocity is zero at its maximum height

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

0=(64ft/s)^2-2(32ft/s^2)(y-960ft)

y=\frac{-(64ft/s)^2-2(32ft/s^2)(960ft)}{-2(32ft/s^2)}=1024ft

So, the projectile goes 1024 ft high

a) From the equation of height we calculate how long does it take to reach maximum point

h=-16t^2+64t+960

1024=-16t^2+64t+960

0=-16t^2+64t-64

Solving the quadratic equation

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=64\\c=-64

t=2s

So, the projectile reach maximum point at t=2s

c) We can calculate the final velocity by using the following formula:

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

v_{y}=±\sqrt{(64ft/s)^{2}-2(32ft/s^2)(-960ft)}=±256ft/s

Since the projectile is going down the velocity at the instant it reaches the ground is:

v=-256ft/s

5 0
3 years ago
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