Answer:
Explanation:
general expression for the ionization energy of any one-electron species.
= z² x ground level energy / n²
z is atomic no , n is energy level .
ground level energy of
H = 1.31 x 10³ kJ/mol
He⁺ = 2² x 1.31 x 10³ kJ/mol = 5.24 x 10³ kJ/mol
Li²⁺ = 3² x 1.31 x 10³ kJ/mol = 1.18 x 10⁴ kJ/mol
b ) the ionization energy of B⁴⁺.
= 5² x 1.31 x 10³ kJ/mol = 32.75 x 10³ kJ/mol
c ) minimum energy required to remove the electron from the n = 3 level of He⁺ per mole
= 5.24 x 10³ / 9 kJ/mol
= 5.82 x 10² kJ/mol
= 5.82 x 10² x 10³ / 6.02 x 10²³ J
.9667 X 10⁻¹⁸ J
= .9667 X 10⁻¹⁸ / 1.6 X 10⁻¹⁹ eV
= 6.042 eV
= 1237.5 / 6.042
= 204.82 nm
=
d )
A. 0.02 mol of O2
B. 0.1 mol of CI2
C. 1 mol of N2
D. 2 mol of H2
Bolded answer is correct.
Answer:
The new volume of gas would be 30 L.
Explanation:
This is an example of a Combined Gas Laws problem.
Answer:
42 19 K→42 20 Ca+e−
Explanation:
Naturally-occurring potassium atoms have a weighted average atomic mass of 39.10 (as seen on most modern versions of the periodic table.) Each potassium atom contains 19 protons p+ and thus an average potassium atom contains about 39.10−19≈20 neutrons n0.
This particular isotope of potassium-42 contains 42 nucleons (i.e., protons and neutrons, combined;) Like other isotopes of potassium 19 out of these nucleons are protons; the rest 42−19=23 are therefore neutrons.
Answer:
\large \boxed{\textbf{609 kJ}}
Explanation:
The formula for the heat absorbed is
q = mCΔT
Data:
m = 2.07 kg
T₁ = 23 °C
T₂ = 191 °C
C = 1.75 J·°C⁻¹g⁻¹
Calculations:
1. Convert kilograms to grams
2.07 kg = 2070 g
2. Calculate ΔT
ΔT = T₂ - T₁ = 191 - 23 = 168 °C
3. Calculate q
