Molar mass of FE2O3=2(55.85)+3(16)=159.7
2.56g*1mol/159.7*2mol/1mol*55.85g/1mol=1.79g
Answer:
8.15 L I2
Explanation:
<u>So, I have the balanced equation of</u>: 2CuBr2 +4KI → 2CuI + 4KBr + I2
<u>Now, we do</u>:
241.6g / 1 mol KI / 1 mol I2 / 22.4 L
--------------------------------------------------------- = 8.15 L I2
/ 166g KI / 4 mol KI / 1 mol I2
Hope this helps! ^u^
The dissociation of formic acid is:
The acid dissociation constant of formic acid, is:
Rearranging the equation:
pH = 2.75
Substituting the values in the equation:
Hence, the ratio is .
<span>The metalloids; boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), polonium (Po) and astatine (At) are the elements found along the step like line between metals and non-metals of the periodic table.</span>