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never [62]
4 years ago
9

The molar mass of water (H2O) is 18.02 g/mol. Yun needs 0.025 mol H2O for a laboratory experiment. She calculates that she needs

72.0 g H2O for the experiment. Is she correct?
Chemistry
2 answers:
Free_Kalibri [48]4 years ago
8 0

The molar mass of water (H2O) is 18.02 g/mol. Yun needs 0.025 mol H2O for a laboratory experiment. She calculates that she needs 72.0 g H2O for the experiment. Is she correct? Answer without doing any calculations.  

She is NOT CORRECT.

The answer is NO!


Tomtit [17]4 years ago
5 0
The relation between moles and mass is given by the formula:


# of moles = (mass in grams) / (molar mass)


So, given the molar mass of 18.02 and 0.025 mol, you can solve the formula for the mass of water in grams:


mass of water in grams = # of moles of water * molar mass of water


mass of water in grams = 0.025 mol * 18.02 g / mol  =   0.4505 g of water.


Then, she is wrong.
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13.3 g of benzene (C6H6) is dissolved in 282 g of carbon tetrachloride. What is the molal concentration of benzene in this solut
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Answer:

0.605 molal

Explanation:

molality is the amount of solute in a particular mass of solvent.

lets calculate the amount of benzene solute.

mass of benzene= 13.3g

molar mass of C6H6= 12*6 +1*6 =72+7=78g/mol

amount of benzene= mass/molar mass

                           =13.3/78

                          =0.1705mol

molality= amount of solute/mass of solvent in kg

mass of solvent=282g=0.282kg

molality = 0.1705/0.282

    =0.605 molal

6 0
3 years ago
The empirical formula for a compound is C2H4NO. If its molar mass is 232.2 g/mol, what is the molecular formula of the compound?
Irina18 [472]

Empirical formula mass

  • C2H4NO
  • 2(12)+4(1)+14+16
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  • 58g/mol

Molar mass=232.2g/mol

Find n

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  • 232.2/58
  • 4

Molecular formula

  • n×Empirical formula
  • 4(C2H4NO)
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2 years ago
Uranium-238 had a half life of 4.5 billion years. A 100 g sample of U-238 has decayed until only 25 g remain. How long did it ta
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3 years ago
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4 0
4 years ago
Someone explain it plz​
timofeeve [1]

Answer:

1). 1 mole of Carbon burnt in air

C + O2 →CO2

1 mole of carbon produces 1 mole of CO2 which is 44g of CO2

2). 1 mole of carbon is burnt in 16g of dioxygen

32g of O2 = 44g of CO2

1g of O2 = 44/32

CO2 (Dioxygen is limiting reagent)

16g of O2 = 4/32 × 16 = 22g of CO2 in one mole

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16g of dioxygen is available, and thus it can combine with 0.5 mol of carbon to give 22g of CO2

4 0
2 years ago
Read 2 more answers
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