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never [62]
4 years ago
9

The molar mass of water (H2O) is 18.02 g/mol. Yun needs 0.025 mol H2O for a laboratory experiment. She calculates that she needs

72.0 g H2O for the experiment. Is she correct?
Chemistry
2 answers:
Free_Kalibri [48]4 years ago
8 0

The molar mass of water (H2O) is 18.02 g/mol. Yun needs 0.025 mol H2O for a laboratory experiment. She calculates that she needs 72.0 g H2O for the experiment. Is she correct? Answer without doing any calculations.  

She is NOT CORRECT.

The answer is NO!


Tomtit [17]4 years ago
5 0
The relation between moles and mass is given by the formula:


# of moles = (mass in grams) / (molar mass)


So, given the molar mass of 18.02 and 0.025 mol, you can solve the formula for the mass of water in grams:


mass of water in grams = # of moles of water * molar mass of water


mass of water in grams = 0.025 mol * 18.02 g / mol  =   0.4505 g of water.


Then, she is wrong.
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Which of the following represents the greatest number of atoms?
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The correct option is B. To get the number of atom for each compound, each element in the compound will be counted as an atom. For instance, for Fe[ClO4]2, there are 1 atom of Fe, 2 atoms of Cl, and 8 atoms of O, making a total of 11 atoms [1 + 2 + 8= 11]. The other options have less than 11 atoms. 
7 0
3 years ago
a gas cylinder contains 2.0 mol of gas X and 6.0 mol of gas Y at a total pressute of 2.1 atm. what is he partial pressure of gas
Igoryamba

The answer is 1.6 atm. Let's first calculate the mole fraction of gas Y.

The mole fraction (x) is: x = n1/n, where n1 is a number of moles of an

individual gas in a mixture and n is total moles of the gas mixture. We

know that n1 of gas Y is 6.0 mol (n1 = 6.0 mol) and that there are in

total 8. mol of the gas mixture (n = 2.0 + 6.0 = 8.0 mol). Now calculate

the mole fraction of gas Y. x = 6.0/8.0 = 0.75. Now, let's use the mole

fraction of gas Y (x) and the total pressure (P) to calculate the

partial pressure of gas Y (P1): x = P1/P. P1 = x * P. If x = 0.75 and P =

2.1 atm, then the partial pressure of gas Y is: P1 = 0.75 * 2.1 atm =

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6 0
4 years ago
Read 2 more answers
Under certain conditions, the substance calcium carbonate can be broken down to form calcium oxide and carbon dioxide. If 31.7 g
klio [65]

Answer:

13.93\ \text{g}

Explanation:

Molecular weight of CaCO_3 = 100.0869 g/mol

Mass of CaCO_3 = 31.7 g

Moles of CaCO_3 = \dfrac{31.7}{100.0869}=0.3167\ \text{mol}

Moles of both CaO and CO_2 is 0.3167\ \text{mol}

Molecular weight of CO_2 = 44 g/mol

Mass of CO_2 = 44\times 0.3167=13.93\ \text{g}

The mass of carbon dioxide formed simultaneously is 13.93\ \text{g}.

6 0
3 years ago
A sample of gas occupies a volume of 67.1 mL . As it expands, it does 135.3 J of work on its surroundings at a constant pressure
Semmy [17]

Answer:

V_2=1.363x10^{-3}m^3=1363mL

Explanation:

Hello,

In this case, since the work done at constant pressure as in isobaric process is computed by:

W= P(V_2-V_1)

Thus, given the pressure, initial volume and work, the final volume is:

V_2=V_1+\frac{W}{P}

Whereas the pressure must be expressed in Pa as the work is given in J (Pa*m³):

P=783Torr*\frac{101325Pa}{760Torr} =104394Pa

And the volumes in m³:

V_1=67.1mL*\frac{1m^3}{1x10^6mL} =6.71x10^{-5}m^3

Thus, the final volume turns out:

V_2=6.71x10^{-5}m^3+\frac{135.3Pa*m^3}{104394Pa}\\\\V_2=1.363x10^{-3}m^3=1363mL

Best regards.

3 0
4 years ago
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