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Natasha_Volkova [10]
3 years ago
5

A base?

Chemistry
2 answers:
KiRa [710]3 years ago
7 0
I think it is A. produces the hydrogen ion

podryga [215]3 years ago
6 0

Answer:

Answer is A

Explanation:

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What is the speed of a car that traveled 40.2km in 2 hours?
PolarNik [594]

Answer:

20 km per hour

Explanation:

7 0
3 years ago
Read 2 more answers
the red line observed in the line spectrum for hydrogen has 3.03x10^-19J, what is the wavelength, in nm, of this?
djverab [1.8K]

Answer:

λ = 6.5604 x 1016 nm

Explanation:

Given Data:

The energy of the red line in Hydrogen Spectra = 3.03 x 10-19

Formula to calculate Wave length

E= hv

Where E is Energy

h is Planks Constant = 6.626 x 10–34 J s

v is frequency

In turn

v= c/ λ

where c is speed of light = 3.00 x 108 m s–1

λ is wavelength = to find

Solution:

Formula to be Used:

E= hv………………………… (1)

Putting the value v in equation 1

               E= h c/ λ…………………… (2)

Put the value in equation 2

3.03 x 10-19 J  = (6.626 x 10–34 J s) x (3.00 x 108 m s–1) / λ ……………………….(3)

By rearranging equation 3

λ = (6.626 x 10–34 J s) x (3.00 x 108 m s–1) /3.03 x 10-19  J

λ = 6.5604 x 107 m

The answer is in “m”

So we have to convert it into nm

So for this to convert “m” to “nm” multiply the answer with 109

λ = 6.5604 x 107 x 109

λ = 6.5604 x 1016 nm

6 0
4 years ago
Based on Charles's law, which of the following statements is true for an ideal gas at a constant pressure and mole amount?
grandymaker [24]

Answer:

Volume is directly proportional to absolute temperature.

Explanation:

5 0
3 years ago
Which of these are examples of passive transport? A. osmosis B.diffusion c. endocytosis d.8 mitosis​
AfilCa [17]

Answer:

Passive Transport

Explanation:

The three examples of passive transport are

Diffuison

Osmosis

facilated diffuison

So the answer can be A or B

4 0
3 years ago
A ring costs $36 more than a bracelet. the cost of the bracelet is 4/7 the cost of the ring. find the total of the two items.
avanturin [10]
So let's use some equations to represent the data [let R= cost of ring & B= cost of bracelet]

R= B + $ 36 .... (1)

B= \frac{4}{7} × R ... (2)

By using simultaneous equations to solve for B and R.
Substitute eq. (1) into eq. (2)

      B =  \frac{4}{7} × (B + $36)

      B = \frac{4}{7}B + \frac{144}{7}

     ( \frac{7}{7}  -  \frac{4}{7} ) B =  \frac{144}{7}

     \frac{3}{7} B =   \frac{144}{7}

⇒  B = $48

By substituting value of B into ea (1)

If R = B + $36
   
   R = ($48) + $36
     
      = $84

∴  <span> the total of the two items = R + B
                                             = $84 + $48
</span>                                             = $132

7 0
3 years ago
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