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3 years ago

11

A student mixes a white solid and a clear liquid together. The solid dissolves into the liquid is evidence of a chemical reactio

n.
True or false

1 answer:

Lana71 [14]3 years ago

6 0

Answer:

false question and change it

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An inverted pyramid is being filled with water at a constant rate of 45 cubic centimeters per second. The pyramid, at the top, h

vaieri [72.5K]

Answer:

13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

Explanation:

Length of the base = l

Width of the base = w

Height of the pyramid = h

Volume of the pyramid = $V=\frac{1}{3}lwh$

We have:

Rate at which water is filled in cube = $\frac{dV}{dt}= 45 cm^3/s$

Square based pyramid:

l = 6 cm, w = 6 cm, h = 13 cm

Volume of the square based pyramid = V

$V=\frac{1}{3}\times l^2\times h$

$\frac{l}{h}=\frac{6}{13}$

$l=\frac{6h}{13}$

$V=\frac{1}{3}\times (\frac{6h}{13})^2\times h$

$V=\frac{12}{169}h^3$

Differentiating V with respect to dt:

$\frac{dV}{dt}=\frac{d(\frac{12}{169}h^3)}{dt}$

$\frac{dV}{dt}=3\times \frac{12}{169}h^2\times \frac{dh}{dt}$

$45 cm^3/s=3\times \frac{12}{169}h^2\times \frac{dh}{dt}$

$\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times h^2}$

Putting, h = 4 cm

$\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times (4 cm)^2}$

$=13.20 cm/s$

13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

3 0

3 years ago

ANSWER ASAP! PLEASE!

Eva8 [605]

Evaporation and straining.and idk the other two

4 0

3 years ago

Physical and chemical changes occur in digestion. What is an example of an physical change in digestion

Korolek [52]

Answer:

teeth chewing food

Explanation:

When teeth chews food it change its state from hard solid to fine substance that can be easily digested by the body i guess

3 0

2 years ago

At stp,a certain mass of gas occupies a volume of 790cm3. find the temperature at which the gas occupies 1000cm3 amd has a press

Luden [163]

The temperature : 332.75 K

<h3>Further explanation</h3>

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

volume of gas = 790 cm³ = 0.79 L

mol of gas at STP :

$\tt \dfrac{0.79}{22.4}=0.035$

Use ideal gas :

$\tt PV=nRT$

P=726 mmHg=0.955 atm

V= 1000 cm³ = 1 L

$\tt T=\dfrac{PV}{nR}\\\\T=\dfrac{0.955\times 1}{0.035\times 0.082}\\\\T=332.75~K$

3 0

2 years ago

PLEASE HELP!!!!!!! (in a few minutes please)

Maslowich

<u>B</u>

Hope this helped you, have a good day bro cya)

6 0

3 years ago

Read 2 more answers