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3 years ago

What is the most important reason to publish results as part of the scientific process?

Chemistry

2 answers:

Makovka662 [10]3 years ago

8 0

It allows other scientists to check findings.

svp [43]3 years ago

4 0

It allows other scientists to check findings is the most important reason to publish results as part of the scientific process.

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In a solution of salt and water which compound is the solute?

ra1l [238]

Solute is what gets dissovled, in this case the salt, and the solVENT is whatever a material is dissolved into, in this case the water.

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3 years ago

All of the noble gasses have 8 valence electrons except _____. helium argon xenon neon this is science

pogonyaev

Helium is the noble gas with only 2 valence electrons

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3 years ago

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Which reaction model represents a nuclear fission reaction?

julsineya [31]

Answer: option B

Explanation: since nuclear fission involves the decay of larger nuclide into smaller nuclei along with Neutron when it is collide with Neutron.

Example Decay of U-235 into Kr and Ba along with 3 neutrons

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3 years ago

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What is the current in the 30 ohm heating coil of a coffee maker that operates on a 120 volt circuit?

SpyIntel [72]

Answer:

4Amps. i can't see other questions clearly

Explanation:

$using ohms law \\ v = ir$

V=120 volt
R=30ohms
I=?

I=V/R

I=120/30

I=4amps

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3 years ago

An unknown amount of Al203 decomposed producing 215 g of solid aluminum. 2Al2O3=4Al+3O2 How many grams of oxygen gas should be p

natulia [17]

Answer:

191.11 grams of oxygen gas should be produced.

Explanation:

The balanced reaction is:

2 Al₂O₃ → 4 Al + 3 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Al₂O₃: 2 moles
Al: 4 moles
O₂: 3 moles

Being the molar mass of each compound:

Al₂O₃: 102 g/mole
Al: 27 g/mole
O₂: 32 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Al₂O₃: 2 moles* 102 g/mole= 204 grams
Al: 4 moles* 27 g/mole= 108 grams
O₂: 3 moles* 32 g/mole= 96 grams

Then you can apply the following rule of three: if by stoichiometry 108 grams of aluminum are produced along with 96 grams of oxygen, 215 grams of aluminum are produced along with how much mass of oxygen?

$mass of oxygen=\frac{215 grams of aluminum*96 grams of oxygen}{108grams of aluminum}$

mass of oxygen= 191.11 grams

191.11 grams of oxygen gas should be produced.

6 0

2 years ago