Take the vector u = <ux, uy> = <4, 3>.
Find the magnitude of u:
||u|| = sqrt[ (ux)^2 + (uy)^2]
||u|| = sqrt[ 4^2 + 3^2 ]
||u|| = sqrt[ 16 + 9 ]
||u|| = sqrt[ 25 ]
||u|| = 5
To find the unit vector in the direction of u, and also with the same sign, just divide each coordinate of u by ||u||. So the vector you are looking for is
u/||u||
u * (1/||u||)
= <4, 3> * (1/5)
= <4/5, 3/5>
and there it is.
Writing it in component form:
= (4/5) * i + (3/5) * j
I hope this helps. =)
So what are we trying to find the reduced fraction or inverse operation
Answer:
Step-by-step explanation:
In Δ AFB,
∠AFB + ∠ABF + ∠A = 180 {Angle sum property of triangle}
90 + 48 + ∠1 = 180
138 + ∠1 = 180
∠1 = 180 - 138
∠1 = 42°
FC // ED and FD is transversal
So, ∠CFD ≅∠EDF {Alternate interior angles are congruent}
∠2 = 39°
In ΔFCD,
∠2 + ∠3 + ∠FCD = 180
39 + ∠3 + 90 = 180
129 +∠3 = 180
∠3 = 180- 129
∠3 = 51°
<span>-x^2 + x-1=0 divide by (-) </span><span><span>
</span>
</span><span>x^2-x+1=0 </span><span><span>
</span>
</span><span>x=1/2(+-) root of (1/2)^2-1 </span><span><span>
</span>
</span><span>x=1/2(+-) root of (1/4)-1 </span><span><span>
</span> </span><span><span>
</span></span><span>x=1/2(+-) root of (1/4)-1 </span>
<span>
x=1/2(+-) root of (1/4)-((4*1)/4) </span>
<span>
x=1/2(+-) root of (-3/4)
</span>
<span>which has not answers, because we can not take a root of negatives numbers</span>
The volume for a pyramid is
, where B is the area of the base and h is the height. We are given the volume, and the base and height in terms of x. Our formula then looks like this:
. Simplifying the right side we have
. Multiply both sides by 18 to get rid of the fraction and we have
, so x = 117.575
