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ivann1987 [24]
3 years ago
13

-x2 + x-1=0

Mathematics
2 answers:
tia_tia [17]3 years ago
5 0
<span>-x^2 + x-1=0 divide by (-) </span><span><span> 
</span>
 </span><span>x^2-x+1=0 </span><span><span> 
</span>
 </span><span>x=1/2(+-) root of (1/2)^2-1 </span><span><span> 
</span>
 </span><span>x=1/2(+-) root of (1/4)-1 </span><span><span> 
</span> </span><span><span> 
</span></span><span>x=1/2(+-) root of (1/4)-1 </span>  
<span>
x=1/2(+-) root of (1/4)-((4*1)/4)  </span> 
<span>
x=1/2(+-) root of (-3/4)   
</span>
 <span>which has not answers, because we can  not take a root of negatives numbers</span>
igomit [66]3 years ago
4 0
Ax² + bx + c = 0
-x² + x - 1= 0
x = <u>-b +/- √b² - 4ac</u>
                2a
x = <u>-1 +/- √1² - 4(-1)(-1)</u>
                  2(-1)
x = <u>-1 +/- √1 - 4</u>
             -2
x = <u>-1 +/- √-3</u>
            -2
x = <u>-1 +/- (-1.732050808)</u>
                  -2
x = <u>-1 - 1.732050808</u>        x = <u>-1 + 1.732050808</u>
                 -2                                      -2
x = <u>-2.732050808</u>             x = <u>0.732050808</u>
              -2                                     -2
x = 1.366025404              x = 0.366025404
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2x2 + 3x = 2. what is x
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Answer:

-2/3

Step-by-step explanation:

4+3x=2

3x=2-4

3x=-2

X= - 2/3

6 0
3 years ago
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6 0
3 years ago
How many solutions 2x+3y=-3 and 3x + 5y = -9
Sunny_sXe [5.5K]
Since the slopes of the two lines are the not equal, they will have only one solution. The solution will be a point and can be found using the method given below.

We can find the solutions by simultaneously solving the two equations.

From first equation, the value of y comes out to be:

2x+3y=-3 \\  \\ &#10;3y=-3-2x \\  \\ &#10;y= \frac{-3-2x}{3}

Using this value of y in second equation, we get:

3x+5( \frac{-3-2x}{3} )=-9 \\  \\ &#10;9x-15-10x=-27 \\  \\ &#10;-x=-27+15 \\  \\ &#10;-x=-12 \\  \\ &#10;x=12

Using this value of x, we can find y:

y= \frac{-3-2x}{3}= \frac{-3-24}{3} =-9

Therefore, there is only one solution to the given equations is which is (12, -9)
8 0
3 years ago
Select the correct answer.
larisa [96]

Answer:

B

Step-by-step explanation:

In this graph we can see a "Parabola", this is the curve for a second degree polynomial function, and based on "Fundamental theorem of algebra" we can know that this polynomial has 2 roots (they can be real or imaginary).

In this graph, the curve doesn't touch the X axis, so we know that this function has not real root. So both roots are complex

8 0
3 years ago
Which represents a function?
VLD [36.1K]

Answer:

\boxed{  \text{Option \: D}}

Step-by-step explanation:

All the relations are not functions. We can determine ( identify ) whether a relation is function or not by drawing a vertical line intersecting the graph of the relation. This is called vertical line test.

  • If the vertical line intersects the graph of a relation at one point , the relation is a function .
  • If it cuts at more than one point , it is not a function. It means that if there are more points of the graph of a relation of a vertical line , same first component ( pre - image ) has more images ( second component ) which is not the function by definition.

--------------------------------------------------

Let's check all of the options :

☐ Option A :

  • The vertical line cuts the graph at two points. So , the graph does not represent a function.

☐ Option B

  • No! This is also not a function as the vertical line cuts the graph at two points.

☐ Option C

  • Nah! This too can't be called a function as the vertical line cuts the graph at two points.

☑ Option D

  • Yep! The vertical line cuts the graph at one point. Thus , the graph represents a function.

Yayy!! We found our answer. It's ' Option D '.

Hope I helped ! ツ

Have a wonderful day / night ! ♡

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

4 0
3 years ago
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