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ivann1987 [24]
3 years ago
13

-x2 + x-1=0

Mathematics
2 answers:
tia_tia [17]3 years ago
5 0
<span>-x^2 + x-1=0 divide by (-) </span><span><span> 
</span>
 </span><span>x^2-x+1=0 </span><span><span> 
</span>
 </span><span>x=1/2(+-) root of (1/2)^2-1 </span><span><span> 
</span>
 </span><span>x=1/2(+-) root of (1/4)-1 </span><span><span> 
</span> </span><span><span> 
</span></span><span>x=1/2(+-) root of (1/4)-1 </span>  
<span>
x=1/2(+-) root of (1/4)-((4*1)/4)  </span> 
<span>
x=1/2(+-) root of (-3/4)   
</span>
 <span>which has not answers, because we can  not take a root of negatives numbers</span>
igomit [66]3 years ago
4 0
Ax² + bx + c = 0
-x² + x - 1= 0
x = <u>-b +/- √b² - 4ac</u>
                2a
x = <u>-1 +/- √1² - 4(-1)(-1)</u>
                  2(-1)
x = <u>-1 +/- √1 - 4</u>
             -2
x = <u>-1 +/- √-3</u>
            -2
x = <u>-1 +/- (-1.732050808)</u>
                  -2
x = <u>-1 - 1.732050808</u>        x = <u>-1 + 1.732050808</u>
                 -2                                      -2
x = <u>-2.732050808</u>             x = <u>0.732050808</u>
              -2                                     -2
x = 1.366025404              x = 0.366025404
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Suppose that P(A|B)=0.2, P(A|B')=0.3, and P(B)=0.7. What is the P(A)? Round your answer to two decimal places (e.g. 98.76).
nata0808 [166]

Answer: P(A) = 0.23

Step-by-step explanation:

Given :

P(A/B) = 0.2

P(A/B^{1})=0.3

P(B)= 0.7

P(A) = ?

From rules of  probability :

P(A) = P(AnB) + P(A n B^{1}) ........................... equation *

P(A n B) can be written as P(A/B) x P(B)

Also , P(A/B^{1}) can be written as  P(A/B^{1}) x P(B^{1})

substituting into equation * , we have

P(A) = P(A/B)P(B) + P(A/B^{1})P(B^{1})

since P(B) = 0.7, then P(B^{1}) = 1 - P(B) = 0.3

so , substituting each values , we have

P(A) = (0.2)(0.7) + (0.3)(0.3)

P(A) = 0.14 + 0.09

P(A) = 0.23

4 0
4 years ago
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