In this case, Coulomb's Law applies:
F = 1/(4πε₀) · (Q₁Q₂/r²)
You can solve it for r:
r = √[1/(4πε₀) · (Q₁Q₂/F<span>)]
Plugging in numbers:
r = </span>√[1/(4π·8.85×10⁻¹²) · (2.5×10⁻⁶)²/0.50]
= 0.335m
The correct answer is: the two charges are 0.335m apart.
Gravitational potential energy=mass*gravitational acceleration*height
Kinetic energy = 0.5*mass*velocity²
So with the given data
K.E 0.5*1*x²=12.5 v²=12.5÷(0.5*1)
v=√12.5÷(0.5*1) v=5
GPE mass*gravitational acceleration*height
1*9.81*h=98
h=98÷(9.81*1)
h= 9.98 m
<span>The Light rays are focused to form real images</span>
Answer:
let me check the answer for you