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3 years ago

HELP!! Explain why a more streamlined car generally will have a better fuel economy than a bulkier car with the same mass.

Physics

2 answers:

Mamont248 [21]3 years ago

8 0

Answer: A streamlined car will be more aerodynamic causing it be more fuel efficient.

Explanation: Aerodynamic-of or having a shape which reduces the drag from air moving past. A bulkier car will be less aerodynamic meaning that the air that hits it won't go around but push it back causing it to use more power which causes it to use more fuel. A streamlined car will allow air to flow around and over the car, a streamlined car will usually be less like a box and have more curves.

Nat2105 [25]3 years ago

6 0

Streamlined means less air resistance. The car will need less force so less fuel in order to overcome air resistance. This will make it more fuel efficient.

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NASA scientists suggest using rotating cylindrical spacecraft to replicate gravity while in a weightless environment. Consider s

dusya [7]

Answer:

Explanation:

Given

diameter of spacecraft $d=148\ m$

radius $r=74\ m$

Force of gravity $F_g$ =mg

where m =mass of object

g=acceleration due to gravity on earth

Suppose v is the speed at which spacecraft is rotating so a net centripetal acceleration is acting on spacecraft which is given by

$F_c=\frac{mv^2}{r}$

$F_c=F_g$

$\frac{mv^2}{r}=mg$

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4 years ago

A 3.20 g sample of a salt dissolves in 9.10 g of water to give a saturated solution at 25°C. a. What is the solubility (in g sal

muminat

Answer:

The solubility of the salt is 35.16 (g/100 g of water).

It would take 71.09 grams of water to dissolve 25 grams of salt.

The percentage of salt that dissolves is 52.7 %

Explanation:

We know that 3.20 grams of salt in 9.10 grams of water gives us a saturated solution at 25°C. To find how many grams of salt will gives us a saturated solution in 100 grams of water at the same temperature, we can use the rule of three.

$\frac{3.20 \g \ salt}{9.10 \ g \ water} = \frac{x \ g \ salt}{100 \ g \ water}$

Working it a little this gives us :

$x = 100 \ g \ water * \frac{3.20 \g \ salt}{9.10 \ g \ water}$

$x = 35.16 \ g \ salt$

So, the solubility of the salt is 35.16 (g/100 g of water).

Using the rule of three, we got:

$\frac{3.20 \g \ salt}{9.10 \ g \ water} = \frac{25 \ g \ salt}{x \ g \ water}$

Working it a little this gives us :

$x = \frac{25 \ g \ salt}{ \frac{3.20 \g \ salt}{9.10 \ g \ water}}$

$x = 71.09 g \ water$

So, it would take 71.09 grams of water to dissolve 25 grams of salt.

Using the rule of three, we got that for 15.0 grams of water the salt dissolved will be:

$\frac{3.20 \g \ salt}{9.10 \ g \ water} = \frac{x \ g \ salt}{15.0 \ g \ water}$

Working it a little this gives us :

$x = 15.0 \ g \ water * \frac{3.20 \g \ salt}{9.10 \ g \ water}$

$x = 5.27\ g \ salt$

This is the salt dissolved

The percentage of salt dissolved is:

$percentage \ salt \ dissolved = 100 \% * \frac{g \ salt \ dissolved}{g \ salt}$

$percentage \ salt \ dissolved = 100 \% * \frac{ 5.27\ g \ salt }{ 10.0 \ g \ salt}$

$percentage \ salt \ dissolved = 52.7 \%$

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