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valina [46]
2 years ago
12

HELP!! Explain why a more streamlined car generally will have a better fuel economy than a bulkier car with the same mass.

Physics
2 answers:
Mamont248 [21]2 years ago
8 0

Answer: A streamlined car will be more aerodynamic causing it be more fuel efficient.

Explanation: Aerodynamic-of or having a shape which reduces the drag from air moving past. A bulkier car will be less aerodynamic meaning that the air that hits it won't go around but push it back causing it to use more power which causes it to use more fuel. A streamlined car will allow air to flow around and over the car, a streamlined car will usually be less like a box and have more curves.

Nat2105 [25]2 years ago
6 0
Streamlined means less air resistance. The car will need less force so less fuel in order to overcome air resistance. This will make it more fuel efficient.
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Ms. Perry travels north 5 km, 10 Km west, and then turns and travels 5 Km 20 points
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Answer:

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a ) The volume of blood flowing per second throughout the vessel is constant .

a₁ v₁ = a₂ v₂

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5 0
3 years ago
Which sequence shows all the spectral colors of the visible light arranged in a decreasing order of their wavelength?
Ad libitum [116K]

Correct answer choice is :


B) Red, orange, yellow, green, blue, indigo, and violet


Explanation:


A spectral color is a color that is extracted in a natural human by a single wavelength of light in the apparent rainbow, or by a comparatively narrow band of wavelengths, also recognized as monochromatic light. The combination of colors provided when the light is separated by a prism. Spectrum an indexed order of the elements of an radiation or wave. Electromagnetic rainbow the complete wavelength spectrum of electromagnetic waves.

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3 years ago
Read 2 more answers
At what frequency should a 200-turn, flat coil of cross sectional area of 300 cm2 be rotated in a uniform 30-mT magnetic field t
stellarik [79]

Answer:

The frequency of the coil is 7.07 Hz

Explanation:

Given;

number of turn of the coil, N = 200 turn

area of the coil, A = 300 cm² = 0.03 m²

magnitude of magnetic field, B = 30 mT = 0.03 T

maximum value of induced emf, E = 8 V

The maximum induced emf in the coil is given by;

E = NBAω

E = NBA(2πf)

f = \frac{E_{max}}{2\pi*NBA}

where;

f is the frequency of the coil

f = \frac{E_{max}}{2\pi*NBA}\\\\f = \frac{8}{2\pi(200)(0.03)(0.03)} \\\\f = 7.07 \ Hz

Therefore, the frequency of the coil is 7.07 Hz

5 0
3 years ago
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