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qaws [65]
3 years ago
15

Nonrenewable energy resources do not include which of the following?

Physics
2 answers:
Tems11 [23]3 years ago
8 0
Hydrogen fuel cells is the answer
Lerok [7]3 years ago
8 0

Answer: The correct answer is-

hydrogen fuel cells.

Hydrogen fuel cells are used for production of electricity whenever it is required. It is an electrochemical cell that is used to generate electricity when it is supplied with hydrogen and oxygen, which together drain as water and generate electricity.

Renewable energy sources are those that can be replenished or renewed naturally ( such as wind power, solar energy, geothermal energy). In other words, these sources of energy never run off.

Hydrogen fuel can be produced by means of renewable energy sources such as wind or solar energy.

Thus, hydrogen fuel cells do not come under non renewable energy resources.

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Discuss the difference between waveform graphs and vibration graphs​
Kitty [74]

Difference exists mainly in the label for x axis.

Explanation:

  • Shapes of waveform and vibration graphs are same.
  • Vibration graphs shows the particle at a single location in the path of the wave when time passes.
  • Waveform graphs shows the particle at multiple locations at a single moment of time.
6 0
3 years ago
Question 10 (1 point)
torisob [31]

Answer:

It does not hit the students face because the speed of the balloon slows down as energy is lost through thermal.

Explanation:

3 0
3 years ago
For a vehicle to negotiate a banked curve in poor weather conditions, where the force of friction f = 0, for a given velocity v
djverab [1.8K]

Answer:

R=240m

Explanation:

From the question we are told that:

Velocity v=25m/s

Force of friction f = 0

Angle \theta=15

Generally the equation for  Radius of curvature is mathematically given by

R=frac{v^2}{tan\theta *g}

R=frac{25^2}{tan 15 *9.81}

R=240m

7 0
3 years ago
A 1.0-μm-diameter oil droplet (density 900 kg/m3) is negatively charged with the addition of 39 extra electrons. It is released
GREYUIT [131]

Answer:

6.75\mu C/m^2

Explanation:

We are given that

Diameter,d=1\mu m=1\time 10^{-6} m

1\mu m=10^{-6} m

Radius,r=\frac{d}{2}=\frac{1}{2}\times 10^{-6}=0.5 \times 10^{-6} m

Density,\rho=900kg/m^3

Total number of electrons,n=39

Charge on electron =1.6\times 10^{-19} C

Total charge=q=ne=39\times 1.6\times 10^{-19}=62.4\times 10^{-19} C

Distance,s=2mm=2\times 10^{-3} m

Mass =density\times volume=900\times \frac{4}{3}\pi r^3=900\times \frac{4}{3}\pi(0.5\times 10^{-6})^3=4.7\times 10^{-16} kg

Initial velocity,u=0

Final speed,v=4.5 m/s

v^2-u^2=2as

(4.5)^2-0=2a(2\times 10^{-3})

20.25=4a\times 10^{-3}

a=\frac{20.25}{4\times 10^{-3}}=5062.5m/s^2

Force,F=ma

qE=ma

q(\frac{\sigma}{2\epsilon_0})=ma

\sigma=\frac{2\epsilon_0ma}{q}=\frac{2\times 8.85\times 10^{-12}\times 4.7\times 10^{-16}\times 5062.5}{62.4\times 10^{-19}}

\epsilon_0=8.85\times 10^{-12}

\sigma=6.75\times 10^{-6}C/m^2=6.75\mu C/m^2

6 0
3 years ago
An object moving at a constant velocity will always have a
SVETLANKA909090 [29]

Answer:

It will always have a zero acceleration

8 0
3 years ago
Read 2 more answers
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