1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iren2701 [21]
3 years ago
6

The spherical side mirror on a car is convex and has a radius of curvature of 25 cm. Another car is following, 20 m behind the m

irror. If the height of the car is 1.6 m, how tall is its image? (A) 5.0 cm (B) 2.0 cm (C) 4.0 cm (D) 0.99 cm
Physics
1 answer:
svlad2 [7]3 years ago
4 0

Answer:

(D) 0.99 cm

Explanation:

Given that the radius of curvature of the mirror is 25 cm.

And another car is following which is behind the mirror of 20 m.

u=20m=2000cm

Focal length is half of the radius of curvature and it is negative for convex lens.

Now the mirror formula.

1/v+1/u=1/f

So,

1/v+1/2000=-1/(25/2)\\1/v=-1/2000-1/12.5\\v=-12.422cm

Now

Magnification is,

m=-v/u

So,

m=12.422/2000=0.00621

So, Height of the image

mh=0.00621\times 1.6 m\\mh=0.0099m\\mh=0.99cm

Therefore, the image height is 0.99 cm.

You might be interested in
1. The hockey puck is given an initial speed of 20.0m/s on a frozen pond. The
andreyandreev [35.5K]
Yurooo iwhvrn u w. N f c
5 0
2 years ago
Read 2 more answers
The first step when doing<br> an<br> investigation is the observe a situation. True or false?
Sunny_sXe [5.5K]

Answer:

True! First step is to make objective observations.

6 0
3 years ago
Read 2 more answers
An aluminum cylinder weighing 30 N, 6 cm in diameter and 40 cm long, is falling concentrically through a long vertical sleeve of
Georgia [21]

Answer: Velocity terminal = 0.093m/s

Explanation:

1. We start by evaluating the gap distance between the two cylinders as h = R(sleeve) - R(cylinder)

= (0.0604/2 - 0.06/2)m

= 2×10^-4

Surface are of the cylinder in the drop, which is required in order to evaluate the shearing stress can be expressed as A(cylinder) = π.d.L

= (π×0.06×0.4)m²

= 0.075m²

Since the force of the cylinder's weight is going to balance the shearing force on the walls, we can express the next equation and derive terminal velocity from it.

Shearing stress = u×V.terminal/h = 0.86×V/0.0002

= 4300Vterminal

Therefore, Fw = shearing stress × A

30N = 4300Vterminal × 0.075

V. terminal = 30/4300 m.s

V. terminal = 0.093m/s

4 0
3 years ago
Compare the mass on Neptune (68.11) to the weight on Neptune (905.863). What is the difference? Why is there a difference?
Alchen [17]
Bbbjv. Jfuzuoud iuzTt45789
7 0
2 years ago
The law of conservation of energy states...
iris [78.8K]
Can neither be created or destroyed.
3 0
3 years ago
Read 2 more answers
Other questions:
  • 1. In a(n) ______________________ circuit, all parts are connected one after another along one path.
    5·2 answers
  • If a ping pong ball and a golf ball are both moving in the same direction with the same amount of kinetic energy, the speed of t
    9·1 answer
  • A student uses a spring with a spring constant of 130 N/m in his projectile apparatus. When 56 J of
    15·1 answer
  • Why do slippery fluids such as oil reduce sliding friction
    14·1 answer
  • An elevator weighing 2.00 x 10 5 N is supported by a steel cable. What is the tension in the cable when the elevator is accelera
    11·1 answer
  • What is the most important factor for the formation of our planets
    7·1 answer
  • An electron initially 3.00 m from a nonconducting infinite sheet of uniformly distributed charge is fired toward the sheet. The
    6·1 answer
  • Is cosine function always used to find x component velocity in resolving vectors
    5·1 answer
  • Two go-carts, A and B, race each other around a 1.0 track. Go-cart A travels at a constant speed of 20.0 /. Go-cart B accelerate
    9·1 answer
  • Object A has a mass of 8.0 kg and is accelerating at 4.0 m/s2. Object B has a mass of 10.0 kg and is accelerating at 3.0 m/s2. O
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!