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iren2701 [21]
3 years ago
6

The spherical side mirror on a car is convex and has a radius of curvature of 25 cm. Another car is following, 20 m behind the m

irror. If the height of the car is 1.6 m, how tall is its image? (A) 5.0 cm (B) 2.0 cm (C) 4.0 cm (D) 0.99 cm
Physics
1 answer:
svlad2 [7]3 years ago
4 0

Answer:

(D) 0.99 cm

Explanation:

Given that the radius of curvature of the mirror is 25 cm.

And another car is following which is behind the mirror of 20 m.

u=20m=2000cm

Focal length is half of the radius of curvature and it is negative for convex lens.

Now the mirror formula.

1/v+1/u=1/f

So,

1/v+1/2000=-1/(25/2)\\1/v=-1/2000-1/12.5\\v=-12.422cm

Now

Magnification is,

m=-v/u

So,

m=12.422/2000=0.00621

So, Height of the image

mh=0.00621\times 1.6 m\\mh=0.0099m\\mh=0.99cm

Therefore, the image height is 0.99 cm.

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Near the equator, the Earth's magnetic field points almost horizontally to the north and has magnitude B=.5 x 10^-4T. What shoul
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6 0
3 years ago
The electric force between two charges A. increases with distance between the charges B. increases if either one of charges gets
beks73 [17]

Answer:

Option (A) , (b) and (d) are correct option

Explanation:

According to Coulomb's law electric force between two charges is given by

F=\frac{1}{4\pi \epsilon _0}\frac{q_1q_2}{r^2}

From the relation we can say that force is directly proportional to magnitude of charges and inversely proportional to distance between them '

So if we increase the distance then force will decrease

Increase if any of the charge get larger

If force is attractive then both the charge will be of different sign and is force is repulsive then both the charges of same sign

From above conclusion we can say that (a), (b) and (d) are correct option

6 0
3 years ago
Gerry is looking at salt under a powerful microscope and notice a crystalline structure.what can be known about the salt sample
Natali [406]

Well, if the salt that Gerry's looking at under a powerful microscope has a crystalline structure, then that's saying that salt is technically a solid.

(I hope that this is an answer you were looking for)

6 0
3 years ago
Consider the interference pattern produced by two parallel slits of width a and separation d, in which d = 3a. The slits are ill
laila [671]

Answer:

a)   m =1  θ = sin⁻¹  λ  / d,  m = 2        θ = sin⁻¹ ( λ  / 2d) ,   c)     m = 3

Explanation:

a) In the interference phenomenon the maxima are given by the expression

         d sin θ = m λ

the maximum for m = 1 is at the angle

          θ = sin⁻¹  λ  / d

the second maximum m = 2

          θ = sin⁻¹ ( λ  / 2d)

the third maximum m = 3

        θ = sin⁻¹ ( λ  / 3d)

the fourth maximum m = 4

       θ = sin⁻¹ ( λ  / 4d)

b) If we take into account the effect of diffraction, the intensity of the maximums is modulated by the envelope of the diffraction of each slit.

       I = I₀ cos² (Ф) (sin x / x)²

       Ф = π d sin θ /λ

       x = pi a sin θ /λ

where a is the width of the slits

with the values ​​of part a are introduced in the expression and we can calculate intensity of each maximum

c) The interference phenomenon gives us maximums of equal intensity and is modulated by the diffraction phenomenon that presents a minimum, when the interference reaches this minimum and is no longer present

maximum interference       d sin θ = m λ

first diffraction minimum    a sin θ = λ

we divide the two expressions

                       d / a = m

In our case

                   3a / a = m

                    m = 3

order three is no longer visible

7 0
3 years ago
7) Sound waves travel with a nominal speed of 340 m/s. Calculate the wavelengths of the following musical notes:
Oksana_A [137]

The wavelength for C1 note is 10.40 m, for A6 note is 0.193 m and for B7 note 0.086 m.

Answer:

Explanation:

Since, wavelength, frequency and speed of sound waves are related to each other, we can determine a single parameter with the help of other two parameters. So in this case, the frequency of different notes are given along with their common speed. So as the frequency is inversely proportional to the wavelength then in this case, the wavelength of the notes will be maximum for C1 and minimum for 3951.1 Hz.

Wavelength = Speed / Frequency

Wavelength for C1 note = 340 / 32.7 =10.40 m

Similarly, the wavelength for A6 note  = 340/1760=0.193 m

And, the wavelength for B7 note = 340/3951.1 = 0.086 m

So, the wavelength for C1 note is 10.40 m, for A6 note is 0.193 m and for B7 note 0.086 m.

6 0
3 years ago
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