Is "ab" an angle? If so, can you try to repost the picture because I cannot see anything so it's hard to try and help you.
Answer:
0.8 Not Outlier
1.1 Not Outlier
10.2 Not Outlier
10.9 Not Outlier
Solution:
Arranging the numbers in ascending order:
0.8 1.1 4.9 5.2 5.8 5.9 6.1 6.1 7.4 10.2 10.9
we can see that the median is 5.9.
We can find the first quartile Q1 by getting the median in the lower half of the data
0.8 1.1 4.9 5.2 5.8
that is, Q1 = 4.9
We can find the third quartile Q3 by getting the median for the upper half of the data
6.1 6.1 7.4 10.2 10.9
that is, Q3 = 7.4
We subtract Q1 from Q3 to find the interquartile range IQR.
IQR = Q3 - Q1 = 7.4 - 4.9 = 2.5
We can now calculate for the upper and lower limits:
upper limit = Q3 + 1.5*IQR = 7.4 + (1.5*2.5) = 11.15
lower limit = Q1 – 1.5*IQR = 0.8 - (1.5*2.5) = -2.95
There is no data point that lies above the upper limit and below the lower limit, therefore, there are no outliers in the data set.
Answer: 433
Step-by-step explanation:
The given sequence : 19,42,65,88,...
We can see that the terms ha common difference as :-
Thus, its an Arithmetic progression with common difference (d)=23
The formula to find the nth term is :-
Now, the 19th term of the given sequence :-
Hence, the 19th term of 19,42,65,88,... is 433.
70°
(the sum of the angles of a triangle is 180°
180 - 40 = 140.
140/2 = 70
The other 2 angles are 70°
70° + 70° + 40° = 180°).
If a divides c,
then 'a' is a factor of 'c'.
Also,
If 'b' divides c,
then 'b' is also a factor of 'c'
therefore,
'a' and 'b' are factors of 'c'
Hence, a and b divides 'c'
so, c = a*b
and ab will also divide c.
Hence, proved.
