Answer: 5.44×10226.022140857(74)×1023⋅mol−1.
Explanation: So the answer is approx. 0.10⋅mol
8 moles I think I’m not sure
Answer:
40 seconds chief just double it
Explanation:
Answer:
6813.7g
Explanation:
Calculate the mass
Let x be the mass
If 1 mol of Fe has a mass of 55.85 g
1 mol =55.85g
122mol= x
we have x= 122•55.85g=6813.7g
Answer:
B. 1.65 L
Explanation:
Step 1: Write the balanced equation
2 SO₂(g) + O₂(g) ⇒ 2 SO₃(g)
Step 2: Calculate the moles of SO₂
The pressure of the gas is 1.20 atm and the temperature 25 °C (298 K). We can calculate the moles using the ideal gas equation.
P × V = n × R × T
n = P × V / R × T
n = 1.20 atm × 1.50 L / (0.0821 atm.L/mol.K) × 298 K = 0.0736 mol
Step 3: Calculate the moles of SO₃ produced
0.0736 mol SO₂ × 2 mol SO₃/2 mol SO₂ = 0.0736 mol SO₃
Step 4: Calculate the volume occupied by 0.0736 moles of SO₃ at STP
At STP, 1 mole of an ideal gas occupies 22.4 L.
0.0736 mol × 22.4 L/1 mol = 1.65 L
