Answer:
1. it is symbolized as 4/2 He
: Alpha rays
2. it has the weakest penetrating power
: Alpha rays
3. It is a high-speed electron
: beta rays
4. It possesses neither mass nor charge
: gamma rays
5. it has the strongest penetrating power
: beta rays
6. its is symbolized as 0/-1e
: beta rays
7. it is the most massive of all the components: alpha rays
Explanation:
Let us consider the characteristics of each of the given rays.
α rays: These are helium nucleus so are symbolized by
Due to two protons and two neutrons unlike beta and gamma rays these are the most massive and thus have least penetrating power among the three given rays.
β rays: These are actually high speed electrons and are symbolized as . Due to lesser mass than alpha rays they are more penetrating than them however less penetrating than gamma rays.
γ rays : They carry no charge or mass. Due to least massive among the three rays they have highest penetrating power.
Answer:
The concentration of Hydrogen Cation is:
Pure water is<u> NEUTRAL</u>
Explanation:
pH = It is negative logarithm of activity of Hydrogen ions.
Activity = concentration for dilute solutions
There are three types of solution based on pH:
1. Acidic solution : Those solution which have pH between 0 to 7 or less than 7 are acidic in nature . They turns blue litmus red.They contain more H+ ions than OH- ions
2. Basic : Those solution which have pH value greater that 7 of between 7 to 14 are basic in nature . They turn red litmus blue.They contain more OH- ions then H+ ions
3 . Neutral : Those solution which have pH = 7 are neutral . They are neither acidic nor basic in nature .They have equa;l concentration of H+ and OH- ions in the solution.
The given water has pH = 7 .This means it is neutral and has low H+ ion concentration in solution. The H+ ion are :
M in water.
OH- =
M in water
So overall neutral
I think it’s 2. Sorry if I’m wrong
Answer:
Option a (100 kPa) is the appropriate option.
Explanation:
The given value is:
Original pressure,
P₁ = 50 kPa
Let the new pressure be "x".
Now,
⇒
On substituting the values, we get
⇒
On applying cross-multiplication, we get
⇒
⇒
Thus the answer above is the right one.