Answer:
I. Friction force exerted on the body is less than 100N
Explanation:
For a body to be static, the moving force must be equal to the frictional force. Since the frictional force is a force of opposition. It tends to oppose the moving force acting on an object.
Hence if the moving force is greater than the force of friction, the Force of fiction will not be able to overcome the moving hence the body will tend to move.
Therefore, for a body to move, Fm > Ff or Ff < Ff
Fm is the moving force
Ff is the force of friction
Given
Fm = 100N
For the 100N body to move the frictional force must be less than 100N
Answer:
(D) 3
Explanation:
The angular momentum is given by:

Thus, the magnitude of the angular momenta of both solar systems are given by:

where we have taken that both systems has the same radius.
By taking into account that T1=3T2, we have

but L1=L2=L:

Hence, the answer is (D) 3
HOPE THIS HELPS!!
Answer:
True
Explanation:
Objects falling through the air experience a force of opposition called air resistance
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