Answer:
f = pl / (l + p)
Explanation:
1/f = 1/p + 1/l
Find the common denominator of the right hand side.
1/f = l/(pl) + p/(pl)
Add:
1/f = (l + p) / (pl)
Take the inverse of both sides:
f = pl / (l + p)
A. Because they reflect their color and absorb all the others
<span>To find the gravitational potential energy of an object, we can use this equation:
GPE = mgh
m is the mass of the object in kg
g = 9.80 m/s^2
h is the height of the object in meters
GPE = mgh
GPE = (0.700 kg) (9.80 m/s^2) (1.5 m)
GPE = 10.3 J
The gravitational potential energy of this can is 10.3 J</span>
Answer:
<em>1.228 x </em>
<em> mm </em>
<em></em>
Explanation:
diameter of aluminium bar D = 40 mm
diameter of hole d = 30 mm
compressive Load F = 180 kN = 180 x 
N
modulus of elasticity E = 85 GN/m^2 = 85 x 
Pa
length of bar L = 600 mm
length of hole = 100 mm
true length of bar = 600 - 100 = 500 mm
area of the bar A = 
= 
= 1256.8 mm^2
area of hole a = 
= 
= 549.85 mm^2
Total contraction of the bar = 
total contraction = 
==> 
= <em>1.228 x </em><em> mm </em>
Answer:
4.7 m³
Explanation:
We'll use the gas law P1 • V1 / T1 = P2 • V2 / T2
* Givens :
P1 = 101 kPa , V1 = 2 m³ , T1 = 300.15 K , P2 = 40 kPa , T2 = 283.15 K
( We must always convert the temperature unit to Kelvin "K")
* What we want to find :
V2 = ?
* Solution :
101 × 2 / 300.15 = 40 × V2 / 283.15
V2 × 40 / 283.15 ≈ 0.67
V2 = 0.67 × 283.15 / 40
V2 ≈ 4.7 m³
