1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Stels [109]
2 years ago
8

A capacitor of cylindrical shape as shown in the red outline, few cm long carries a uniformly distributed charge of 7.2 uC per m

eter of length. By constructing a suitable Gaussian surface around the wire, Find the magnitude and direction of the electric field at points
a)5.5m

b)2.5m

perpendicular from the center of the wire.​
Physics
1 answer:
Natali [406]2 years ago
4 0

(a) The magnitude of the electric field at point 5.5m is 2.35 x 10⁴ N/C.

(b) The magnitude of the electric field at point 2.5m is 5.18 x 10⁴ N/C.

<h3>Electric field at a point on the Gaussian surface</h3>

The magnitude of the electric field at a point on the cylindrical Gaussian surface is calculated as follows;

E = λ/2πε₀r

where;

  • λ is linear charge density
  • ε₀ is permitivity of free space
  • r is the position of the charge
<h3>At a distance of 5.5 m</h3>

E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 5.5} \\\\E = 2.35 \times 10^4 \ N/C

<h3>At a distance of 2.5 m</h3>

E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 2.5} \\\\E = 5.18 \times 10^4 \ N/C

Thus, the magnitude of the electric field at points of 5.5m is 2.35 x 10⁴ N/C, and the magnitude of the electric field at points of 2.5m is 5.18 x 10⁴ N/C.

Learn more about electric field here: brainly.com/question/14372859

You might be interested in
Why would a flat sheet of paper and a wad of paper with the same mass not fall through the air at the same rate?
Gelneren [198K]
The flat sheet of paper has more surface area than the crumpled ball
7 0
3 years ago
Read 2 more answers
If a radio wave carries information by changing the amplitude of the transmitted wave, what kind of broadcast might it possibly
mariarad [96]
Option A because those are the correct ones
4 0
2 years ago
The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of g
Morgarella [4.7K]

Here is the full question:

The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent hoop about that axis, if the hoop has the same mass M and a radius k given by:  

k=\sqrt{\frac{I}{M} }

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of gyration of (a) a cylinder of radius 1.20 m, (b) a thin spherical shell of radius 1.20 m, and (c) a solid sphere of radius 1.20 m, all rotating about their central axes.

Answer:

a) 0.85 m

b) 0.98 m

c) 0.76 m

Explanation:

Given that: the radius of gyration  k=\sqrt{\frac{I}{M} }

So, moment of rotational inertia (I) of a cylinder about it axis = \frac{MR^2}{2}

k=\sqrt{\frac{\frac{MR^2}{2}}{M} }

k=\sqrt{{\frac{MR^2}{2}}* \frac{1}{M} }

k=\sqrt{{\frac{R^2}{2}}

k={\frac{R}{\sqrt{2}}

k={\frac{1.20m}{\sqrt{2}}

k = 0.8455 m

k ≅ 0.85 m

For the spherical shell of radius

(I) = \frac{2}{3}MR^2

k = \sqrt{\frac{\frac{2}{3}MR^2}{M}  }

k = \sqrt{\frac{2}{3} R^2}

k = \sqrt{\frac{2}{3} }*R

k = \sqrt{\frac{2}{3}}  *1.20

k = 0.9797 m

k ≅ 0.98 m

For the solid sphere of  radius

(I) = \frac{2}{5}MR^2

k = \sqrt{\frac{\frac{2}{5}MR^2}{M}  }

k = \sqrt{\frac{2}{5} R^2}

k = \sqrt{\frac{2}{5} }*R

k = \sqrt{\frac{2}{5}}  *1.20

k = 0.7560

k ≅ 0.76 m

6 0
3 years ago
Does moon have a dense atmosphere
nata0808 [166]

Answer:

No

Explanation:

Moon does not have any atmosphere.

Please mark as brainliest

3 0
3 years ago
Suppose that you purchased a water bed with the dimensions 2.55 m à 2.53 dm à 245 cm. what mass of water does this bed contain
Nadya [2.5K]

dimensions of the bed is given as

length = 2.55 m

thickness = 2.53 dm = 0.253 m

width = 245 cm = 2.45 m

now the volume of the bed is given as

V = 2.55 * 0.253 * 2.45 m^3

V = 1.581m^3

now the mass of water in it is given as

mass = density * volume

mass = 1000* 1.581

mass = 1581 kg

<em>so it will contain 1581 kg mass in it</em>

6 0
3 years ago
Other questions:
  • Which of the following terms describes the primary core of a comet?
    9·1 answer
  • The Earth's gravity keeps us from flying out to space. How can you explain that we have a stronger gravitational attraction to t
    13·1 answer
  • The FIRST space station placed into orbit around the earth followed by a team sent from earth to link up with the station was de
    6·2 answers
  • Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first bl
    10·1 answer
  • Which two points on the wave shown in the diagram below are in phase with each other?
    14·1 answer
  • A ring with an 18mm diameter falls off a scientist's finger into the solenoid in the lab. The solenoid is 25 cm long, 5.0 cm in
    10·1 answer
  • Explain why gases are more compressible than solid
    13·1 answer
  • Waves can transfer energy through
    8·1 answer
  • Which of the following quantities are unknown? initial separation of the particles final separation of the particles initial spe
    15·1 answer
  • A sub-woofer is a type of speaker which plays only the very low notes in a song or movie. Which of the following frequencies wou
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!