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ss7ja [257]
3 years ago
15

The density of a pure substance is its mass per unit volume. The density of cresol has been measured to be 1024 g/L . Calculate

the mass of 405mL of cresol.
Chemistry
1 answer:
Ierofanga [76]3 years ago
3 0

Answer: The mass of 405 ml of cresol is 415 grams

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{volume}

Given : Density of cresol = 1024 g/L

Volume of cresol = 405 ml = 0.405 L   ( 1L=1000ml)

Putting in the values we get:

1024g/L=\frac{mass}{0.405L}

mass=1024g/L\times 0.405L=415g

Thus mass of 405 ml of cresol is 415 grams

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ATOMIC number of element A is 3

Explanation:

Atomic number is the same as number of protons of an element.

according to the periodic table, Lithium is the element with 3 protons in its neutral state and it's atomic number is 3.

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Which of the following are advantages of the SI system?
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The correct answer is A, B and C
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A solution of acetic acid and water contains 205.0 g L-1 of acetic acid and 820.0 g L-1 of water. Compute the density of the sol
LekaFEV [45]

Answer:

\rho_t=1025000 gmL^{-1}

Explanation:

From the question we are told that:

Density of acetic acid \rho_a=205 gL^{-1}

Density of Water \rho_w=820 gL^{-1}

Generally the equation for Solution Density is mathematically given by

\rho_t= \rho_w+\rho_a

\rho_t=205+820

\rho_t=1025 gL^{-1}

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During a lab, a student holds a magnesium ribbon in a flame. Which of the following is the magnesium ribbon considered?
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2 years ago
Muriatic acid, HCl, is often used to remove rust. A solution of muriatic acid, HCl, reacts with Fe2O3 deposits on industrial equ
Alina [70]

Answer:

3L

Explanation:

Step 1:

The balanced equation for the reaction.

Fe2O3(s) + 6HCl(aq) → 2FeCl3(aq) + 3H2O

Step 2 :

Determination of the masses of HCl and Fe2O3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Fe2O3 = 159.70g/mol

Molar mass of HCl = 36.46 g/mol

Mass of HCl from the balanced equation = 6 x 36.46 = 218.76g

From the balanced equation above,

159.70g of Fe2O3 reacted with 218.76g of HCl

Step 3:

Determination of the mass of HCl needed to react with 439g of Fe2O3. This is illustrated below:

From the balanced equation above,

159.70g of Fe2O3 reacted with 218.76g of HCl.

Therefore, 439g of Fe2O3 will react with = (439 x 218.76) /159.70 = 601.35g of HCl.

Step 4:

Conversion of 601.35g of HCl to mole. This is illustrated below:

Molar mass of HCl = 36.46 g/mol

Mass of HCl = 601.35g

Number of mole = Mass/Molar Mass

Number of mole of HCl = 601.35/36.46

Number of mole of HCl = 16.49 moles

Step 5:

Determination of the volume of the HCl that reacted.

This is illustrated below:

Mole of HCl = 16.49 moles

Molarity of HCl = 5.50 M

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 16.49/5.5

Volume of HCl = 3L

Therefore the volume of HCl needed for the reaction is 3L

5 0
2 years ago
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