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sertanlavr [38]
3 years ago
12

How many liters of water need to be added to 0.5 moles of CaCl2 to make a 0.20 M solution of CaCl2?

Chemistry
1 answer:
vlabodo [156]3 years ago
4 0

Answer:

2.5M

Explanation:

Molarity is the measure of the molar concentration of a solution. It is calculated using the formula below:

Molarity = n/V

Where;

n = number of moles (mol)

V = volume (L)

According to the information about Calcium chloride (CaCl2) provided in this question;

n = 0.5moles

M = 0.20M

Molarity = 0.5/0.2

Molarity = 2.5M

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A person tries to heat up her bath water by adding 5.0 l of water at 80c to 60 l of water at 30c. what is the final temperature
Sophie [7]
We can calculate the final temperature from this formula :

when Tf = (V1* T1) +(V2* T2) / (V1+ V2)

when V1 is the first volume of water = 5 L 

and V2 is the second  volume of water = 60 L

and T1 is the first temperature of water in Kelvin = 80 °C +273 = 353 K

and T2 is the second temperature of water in Kelvin =  30°C + 273= 303 K

and Tf is the final temperature of water in Kelvin 

so, by substitution:

Tf = (5 L * 353 K ) + ( 60 L * 303 K) / ( 5 L + 60 L)

     = 1765 + 18180 / 65 L

     = 306 K
     = 306 -273 = 33° C

8 0
3 years ago
PLEASE HELP!!!
trasher [3.6K]

Answer:

(a) oxygen

(b) 154g (to 3sf)

(c) 79.9% (to 3sf)

Explanation:

mass (g) = moles × Mr/Ar

note: eqn means chemical equation

(a)

moles of P = 84.1 ÷ 30.973 = 2.7152 moles

moles of O2 = 85÷2(16) = 2.65625 moles

Assuming all the moles of P is used up,

moles of O2 / moles of phosphorus = 5/4 (according to balanced chemical eqn)

moles of O2 required = 5/4 × 2.7152moles = 3.394 moles (more than supplied which is 2.65625moles)

therefore there is insufficient moles of O2 and the limiting reactant is oxygen.

(b)

moles of P2O5 produced

= 2/5 (according to eqn) × 2.7152

= 1.08608moles

mass of P2O5 produced

= 1.08608 × [ 2(30.973) + 5(16) ]

= 154.164g

= approx. 154g to 3 sig. fig.

(c)

% yield = actual/theoretical yield × 100%

= 123/154 × 100%

= 79.870%

= approx. 79.9% (to 3sf)

4 0
3 years ago
A student makes the following two claims about chemical reactions:
Svet_ta [14]
I would agree with the second one, not the first. You can't always see the chemical reaction, and it isn't always sudden. But the second claim is true. 
7 0
3 years ago
3.79 x 10^8<br> =<br> .mol<br> 2<br> 2<br> kg.m<br> g.cm
yuradex [85]

Answer:

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3 0
3 years ago
A solution made by dissolving 9.81 g of a nonvolatile, nonelectrolyte in 90.0 g of water boiled at 100.37 °C at 760 mm Hg. What
NISA [10]

Answer:

151 g/mol

Explanation:

In order to solve this problem we need to keep in mind the formula for the <em>boiling point elevation</em>:

  • ΔT = Kb * <em>m</em> * i

Where:

  • ΔT is the temperature difference between the boiling point of the solution and that of pure water. 100.37 °C - 100.00 °C = 0.37 °C.
  • <em>m</em> is the molarity of the solution
  • i is the van't Hoff factor. As the solute is a nonelectrolyte, the factor is 1.

Input the data and <u>calculate </u><em><u>m</u></em>:

  • 0.37 °C = 0.51 °C/m * <em>m</em> * 1
  • <em>m</em> =0.72 m

We now can <u>calculate the number of moles of the substance</u>, using the <em>definition of molarity</em>:

  • molarity = moles of solute / kg of solvent

In this case kg of solvent = 90.0 g / 1000 = 0.090 kg

  • 0.72 m = moles / 0.090 kg
  • moles = 0.065 mol

Finally we <u>calculate the molar mass</u>, using the <em>number of moles and the mass</em>:

  • 9.81 g / 0.065 mol = 151 g/mol
8 0
3 years ago
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