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sertanlavr [38]
3 years ago
12

How many liters of water need to be added to 0.5 moles of CaCl2 to make a 0.20 M solution of CaCl2?

Chemistry
1 answer:
vlabodo [156]3 years ago
4 0

Answer:

2.5M

Explanation:

Molarity is the measure of the molar concentration of a solution. It is calculated using the formula below:

Molarity = n/V

Where;

n = number of moles (mol)

V = volume (L)

According to the information about Calcium chloride (CaCl2) provided in this question;

n = 0.5moles

M = 0.20M

Molarity = 0.5/0.2

Molarity = 2.5M

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Calculate the volume 3.00 moles of a gas will occupy at 24.0˚C and 1.003 atm. *
vitfil [10]

Answer: 72.93 litres

Explanation:

Given that:

Volume of gas (V) = ?

Temperature (T) = 24.0°C

Convert 24.0°C to Kelvin by adding 273

(24.0°C + 273 = 297K)

Pressure (P) = 1.003 atm

Number of moles (n) = 3 moles

Molar gas constant (R) is a constant with a value of 0.0821 atm L K-1 mol-1

Then, apply ideal gas equation

pV = nRT

1.003 atm x V = 3.00 moles x 0.0821 atm L K-1 mol-1 x 297K

1.003 atm•V = 73.15 atm•L

Divide both sides by 1.003 atm

1.003 atm•V/1.003 atm = 73.15 atm•L/1.003 atm

V = 72.93 L

Thus, the volume of the gas is 72.93 litres

5 0
3 years ago
How many grams of CaF2 would be needed to produce 1.12 moles of F2?
zlopas [31]

Step 1 : Write balanced chemical equation.

CaF₂ can be converted to F₂ in 2 steps. The reactions are mentioned below.

I] CaF_{2} + H_{2} SO_{4} -------> 2HF + CaSO_{4}

II] 2HF -------> H_{2} + F_{2}

The final balanced equation for this reaction can be written as

CaF_{2} + H_{2} SO_{4} --------->  CaSO_{4} + H_{2} + F_{2}

Step 2: Find moles of CaF₂ Using balanced equation

We have 1.12 mol F₂

The mole ratio of CaF₂ and F₂ is 1:1

1.12mol F_{2} *  \frac{1molCaF_{2}}{1molF_{2}}    = 1.12molCaF_{2}

Step 3 : Calculate molar mass of CaF2.

Molar mass of CaF₂ can be calculated by adding atomic masses of Ca and F

Molar mass of CaF₂ = Ca + 2 (F)

Molar mass of CaF₂ = 40.08 + 18.998 = 78.08 g

Step 4 : Find grams of CaF₂

Grams of CaF₂ = 1.12molCaF_{2} *\frac{78.08gCaF_{2}}{1mol CaF_{2}}

Grams of CaF₂ = 87.45 g

87.45 grams of CaF2 would be needed to produce 1.12 moles of F2.

4 0
2 years ago
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PIT_PIT [208]
A + B = Products
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3 years ago
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Answer:

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Answer:

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Explanation:

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