Answer:
M = 0.138 M
Explanation:
Given data:
Mass of glucose = 12.55 g
Volume of solution = 500 mL
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of glucose:
Number of moles = mass/molar mass
Number of moles = 12.55 g/ 180.156 g/mol
Number of moles = 0.069 mol
Volume in L:
500 mL × 1 L /1000 mL
0.5 L
Molarity:
M = 0.069 mol / 0.5 L
M = 0.138 M
A
Explanation:
The coiling up of DNA with the help of histone proteins - to what is called heterochromatic regions- is part of gene regulation. This makes genes inaccessible to RNA polymerase that makes mRNA from the genes. When the genes are exposed by DNA unwinding, these genes are transcribed and the resulting mRNAs are translated by ribosomes into proteins.
The DNA never unwinds completely, but rather does so region by region, because if it does so it would become so long that it wouldn't fit in the nucleus or cell.
Answer:
2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF
Explanation:
AlF₃ + Li₂O —> Al₂O₃ + LiF
The above equation can be balanced as follow:
AlF₃ + Li₂O —> Al₂O₃ + LiF
There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by writing 2 before AlF₃ as shown below:
2AlF₃ + Li₂O —> Al₂O₃ + LiF
There are 6 atoms of F on the left side and 1 atom on the right side. It can be balance by writing 6 before LiF as shown below:
2AlF₃ + Li₂O —> Al₂O₃ + 6LiF
There are 2 atoms of Li on the left side and 6 atoms on the right side. It can be balance by writing 3 before Li₂O as shown below:
2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF
Thus, the equation is balanced..!
Answer:
a). P = 688 atm
b). P = 1083.04 atm
c).Δ G = 16.188 J/mol
Explanation:
a). Fugacity 'f' can be calculated from the following equations :
where, P = pressure , Z = compressibility
Now, the virial equation is :
........(1)
Also, PV=ZRT for real gases .......(2)
∴ 
So from the fugacity equation ,
Putting the value of P = 500 atm in the above equation, we get,
f = 688 atm
b). Given f = 2P
∴ P = 1083.04 atm
c). dG = Vdp -S dt at constant temperature, dT = 0
Therefore, dG = V dp
![$\Delta G=R[\ln\frac{P_2}{P_1}+6.4 \times 10^{-4}(P_2-P_1)]$](https://tex.z-dn.net/?f=%24%5CDelta%20G%3DR%5B%5Cln%5Cfrac%7BP_2%7D%7BP_1%7D%2B6.4%20%5Ctimes%2010%5E%7B-4%7D%28P_2-P_1%29%5D%24)
![$\Delta G=8.314\times 298[\ln\frac{500}{1}+6.4 \times 10^{-4}(500-1)]$](https://tex.z-dn.net/?f=%24%5CDelta%20G%3D8.314%5Ctimes%20298%5B%5Cln%5Cfrac%7B500%7D%7B1%7D%2B6.4%20%5Ctimes%2010%5E%7B-4%7D%28500-1%29%5D%24)
Δ G = 16.188 J/mol
First we calculate the number of moles of sugar (which I assume is sucrose).
number of moles = mass / molecular weight
number of moles of sugar = 19 / 342 = 0.055 moles
Now we may calculate the molarity of the solution.
molarity = number of moles / solution volume (L)
molarity = 0.055 / 0.05 = 1.1 M
