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hodyreva [135]
3 years ago
8

A helium balloon containing 5m³ of gas at a pressure of 30kPa is released into the air. Assuming that the temperature is constan

t calculate the volume the balloon would have when the pressure inside the balloon has fallen to 5kPa. Answer in m³.
Physics
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

30 m³

Explanation:

Parameters given:

Initial volume of helium, V1 = 5 m³

Initial pressure in balloon, P1 = 30 kPa

Final pressure, P2 = 5 kPa

To find the volume of the balloon at that volume, we apply Boyle's law.

It states that at constant temperature, the pressure of a gas is inversely proportional to the volume of the gas.

Mathematically:

P = k / V

Where k = constant of proportionality

This implies that:

P * V = k

This means that if the pressure or volume of the gas changes at the same temperature, the product of the pressure and volume would be the same:

Hence:

P1 * V1 = P2 * V2

Hence, to find the final volume:

30 * 5 = 5 * V2

=> V2 = (30 * 5) / 5

V2 = 30 m³

The volume of the gas when the pressure is 5 kPa is 30 m³.

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2 years ago
If the distance to a point source of sound is doubled, by what multiplicative factor does the intensity change?
alina1380 [7]

If the distance to a point source of sound is doubled, by a multiplicative factor of 4, the intensity changes.

Intensity of sound is the sound which is perpendicular to sound wave propogation per unit area. It is dependent on the Surface of source sound.

Intensity is the Power per unit area. Its SI unit is Watt/m².

As we move away from a source of sound, the sound starts to diminish. This is due to the decreasing sound intensity with distance.

It can also be understood by the fact that on increasing distance, the Power radiated by the source spreads over a larger area. Hence, the Intensity decreases gradually.

Since, Intensity is proportional to the square of the distance.

Hence, on doubling the distance, Intensity reduces to one fourth of the initial intensity or reduces by a multiplicative factor of 4.

Learn more about Intensity here, brainly.com/question/17583145

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8 0
1 year ago
A child in danger of drowning in a river is being carried downstream by a current that flows due south uniformly with a speed of
tia_tia [17]

Let the rescue boat starts at an angle theta with the North

now its velocity towards East is given as

v_x = 24sin\theta

v_y = -24cos\theta + 3

now in some time "t" it will catch the boy

so we will have

t = \frac{0.5}{24sin\theta}

also we have

t = \frac{2}{-24cos\theta + 3}

now we have

\frac{2}{-24cos\theta + 3} = \frac{0.5}{24sin\theta}

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3 years ago
A parallel-plate capacitor has a voltage of 391 v applied across its plates, then the voltage source is removed. what is the vol
andrezito [222]

When the capacitor is connected to the voltage, a charge Q is stored on its plates. Calling C_0 the capacitance of the capacitor in air, the charge Q, the capacitance C_0 and the voltage (V_0=391 V) are related by

C_0 =\frac{Q}{V_0} (1)


when the source is disconnected the charge Q remains on the capacitor.


When the space between the plates is filled with mica, the capacitance of the capacitor increases by a factor 5.4 (the permittivity of the mica compared to that of the air):

C=k C_0 = 5.4 C_0

this is the new capacitance. Since the charge Q on the plates remains the same, by using eq. (1) we can find the new voltage across the capacitor:

V=\frac{Q}{C}=\frac{Q}{5.4 C_0}

And since Q=C_0 V_0, substituting into the previous equation, we find:

V=\frac{C_0 V_0}{5.4 C_0}=\frac{V_0}{5.4}=\frac{391 V}{5.4}=72.4 V



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