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Oliga [24]
2 years ago
9

Suppose the position of a particle moving along the x-axis given by the equation X=(1m/s²)t²-(5m/s)t +0.5m

Physics
1 answer:
Rama09 [41]2 years ago
5 0

Answer:

sorry i dont know

Explanation:

i dont know

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Who discovered Absolute Temperature​
zepelin [54]

Answer: William Thomson, better known as Lord Kelvin

5 0
3 years ago
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A 0.02kg dart is loaded into a toy spring gun by compressing the spring 6cm. If the spring has a constant of 20 N/m, find… a. Th
katrin2010 [14]

Answer:

a) 0.036 J b) 0.036J c) 0.036 d) 1.9m/s e) 0.18 m

Explanation:

Mass of the dart = 0.02kg, the spring was compressed to 6cm

Work needed to compress the spring = 1/2*k*x ^2 where k is the force constant of the spring in N/m, x is the distance it was compressed in m

Work needed to compress the spring = 0.5 * 20* 0.06^2 since 6cm = 6 / 100 = 0.06 m

Work needed to compress the spring = 0.036J

b) the total energy stored in the spring = the work done to compress the spring = 0.036J

c) kinetic energy of the dart as it leaves the the spring = elastic potential energy stored in the spring = the work done in compressing the = 0.036J using the law of conservation of energy; energy is neither created nor destroyed but transformed from one form to another.

d) 1/2mv^2 = 0.036

mv^2 = 0.036*2

v^2 = 0.036*2 / 0.02 = 3.6

v = √3.6 = 1.897 approx 1.9m/s

e) kinetic energy of the dart = work done against gravity to get the body to height h

Work done against gravity = potential energy conserved at height = -mgh g is negative because the motion is upward while gravity acts downward

0.036 = 0.02 * 9.81 * h

0.036 / ( 0.02*9.81) = h

h = 0.18 m

6 0
3 years ago
A slice of cheese has a mass of 40 g and a volume of 23 cm^3. What is the density of the cheese in units of g/cm^3 and g/mL?
Mila [183]

The mathematical and proportional relationship between mL and cm ^ 3 said us that 1cm ^ 3 is equivalent to 1mL.

If the density is considered as the amount of mass per unit volume we will have to

\rho = \frac{m}{V}

here,

m = mass

V = Volume

Replacing we have that

\rho = \frac{40g}{23cm^3}

\rho = 1.739g/cm^3

As 1mL = 1cm^3 we have that the density in g/mL is,

\rho = 1.739g/mL

6 0
3 years ago
You run to your girlfriend's house and announce that you were running at a rate of 15 miles per hour. She knows this is not true
Sunny_sXe [5.5K]

Answer:how long it took you to get there and the distance between your house and her house

Explanation:

8 0
3 years ago
Help pls.!! and explain please
umka2103 [35]

Answer:

so if it's 20 you should put 20 times 10 15 * 30 and 1.3 * 5 mg and if you put that milligrams in there it'll solve the destination I saw the white way you going so yeah just be careful at least you want to make the milligrams even a multimacy with the y i and replace it with the 14a

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3 years ago
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