Ask question

Ask question

All categories

3 years ago

13

assuming that there are no outside forces, what will happen if two neutral atoms are placed 1 M apart in a vacuum. a)the atoms w

ill orbit each other b)the atoms will remain stationary c) the atoms will move tword each other d) the atoms will move away from each other.

1 answer:

timurjin [86]3 years ago

7 0

D the atoms will move tword each other hope this helps

You might be interested in

If a cliff jumper leaps off the edge of a 100m cliff, how long does she fall before hitting the water? (assume zero air resistan

andrew-mc [135]

<h2>Answer:</h2>

<em>Hello, </em>

<h3><u>QUESTION)</u></h3>

Assuming that the initial velocity of the jumper is zero, on Earth any freely falling object has an acceleration of 9.8 m/s².

<em>✔ We have : a = v/Δt = ⇔ Δt = v/a </em>

Δt = (√2xgxh)/9,8
Δt = (14√10)/9,8
Δt ≈ 4,5 s

4 0

2 years ago

A pendulum is made by letting a 4 kg mass swing at the end of a string that has a length of 1.5 meter. The maximum angle that th

olga nikolaevna [1]

Answer:

Approximately $7.8\; \rm J$ .

Explanation:

The change in the gravitational potential energy of the pendulum is directly related to the change in its height.

Refer to the sketch attached. The pendulum is initially at $\rm P_2$ . Its highest point is at $P_1$ . The length of segment $\rm BP_2$ gives the change in its height.

The lengths of $\rm AP_1$ and $\rm AP_2$ are simply the length of the string, $1.5\; \rm m$ . To find the length of $\rm BP_2$ , start by calculating the length of $\rm AB$ .

$\rm AB$ forms a leg in the right triangle $\rm \triangle AP_1B$ . Besides, it is adjacent to the $30^\circ$ angle $\rm P_1\hat{A}B$ . Its length would be:

$\rm AB = 1.5 \times \cos(30^\circ) \approx 1.30\; \rm m$ .

The length of $\rm BP_2$ would thus be

$\rm BP_2 = AP_2 - AB = 1.5 - 1.30 \approx 0.20\; \rm m$ .

The change in gravitational potential energy can be found with the equation

$\Delta \mathrm{GPE} = m \cdot g \cdot \Delta h$ . In this equation,

$m$ is the mass of the object,
$g \approx 9.81\; \rm N \cdot kg^{-1}$ near the surface of the earth, and
$\Delta h$ is the change in the object's height.

In this case, $m = 4\; \rm kg$ and $\Delta h \approx 0.20\; \rm m$ . Therefore:

$\Delta \mathrm{GPE} = 4 \times 9.81 \times 0.20 \approx 7.8\; \rm J$ .

6 0

2 years ago

Find an equation of the line which is parallel to 2x-3y=6 and passes through the point (6,9)

tatuchka [14]

Step 2: Use the slope to find<span> the y-intercept. </span>Line<span> is </span>parallel<span> so use m = 2/5. </span>6<span>. </span>Find<span>the </span>equation<span> of a </span>line passing through the point<span> (8, –</span>9<span>) perpendicular to the </span>line<span> 3x + 8y = 4.</span>

8 0

3 years ago

Graphs often permit scientists to make estimations for items when there is no data. Please select the best answer from the choic

Zinaida [17]

Answer:

no they don't but I think it's 8

3 0

1 year ago

A dog has a mass of 60kg and an acceleration of 2m/s/s. What is the force of the dog?

attashe74 [19]

Answer:

120 N

Explanation:

F=ma therefore 60kg times 2m/s^2 is 120 N

8 0

2 years ago