The density of the gold is calculated to be "19,300 kg/m³".
<u>Explanation:</u>
Given:
Volume = 2cm³
Mass = 38.6 grams.
To Find:
Density of the gold = ?
Solution:
Density is obtained by dividing mass of the sample by its volume and it is given in the units of kg/m³.
Mass in grams is converted into kg as,
1 g = 0.001 kg
38. 6 g = 
Now we have to convert cm³ to m³ as,
1 cm³ = 10⁻⁶ m³
2 cm³ = 2 × 10⁻⁶ m³
So Density = 
Physical properties of Gold:
- It is Malleable and ductile.
- It is a corrosion resistant element.
Answer:
F = 1958.4 N
Explanation:
By volume conservation of the fluid on both sides we can say that volume of fluid displaced on the side of the car must be equal to the volume of fluid on the other side
so we have
so the car will lift upwards by distance 1.2 m and the other side will go down by distance 15.55 m
So here the net pressure on the smaller area is given as
excess pressure exerted on the smaller area is given as
now the force required on the other side is given as
Answer:
4
Explanation:
As you can see in the free body diagram there are 4 forces acting on the body.
Answer:
0.82052 m
Explanation:
potential energy of spring = kinetic energy
=> 0.5kx^2 = 0.5mv^2
=> 
v= 3.11127 m/s
angle = 37°
thus height = distance×sin(37) = D×0.60182
Also,
m×g×h = 0.5×m×v^2
=> 2×9.8×D×0.60182 = 0.5×2×3.11127×3.11127
=> D = 0.82052 m
120 minutes=2 hours
20/2= 10mph
