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SpyIntel [72]
3 years ago
5

Work out this problem if an object weighs 34.8 grams and has a volume of 22.8ml , what is this object's density?

Physics
2 answers:
Stels [109]3 years ago
5 0
We know, density = Mass / volume
Here, mass = 34.8 g
v = 22.8 ml = 22.8 cm³

Substitute their values, 
d = 34.8/22.8
d = 1.52 g/cm³

Hope this helps!
pishuonlain [190]3 years ago
3 0
Density = Mass / Volume
 
            = 34.8 g / 22.8 ml       ≈ 1.5263 g/mL

Density is  ≈ 1.5263 g/mL

Hope this explains it.
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1300 m east = 1300 i

2400 m north = 2400 j

Drops the penny from a cliff 640 m high = -640 k

Displacement of penny = 1300 i + 2400 j - 640 k

b) Displacement of man for return trip = -1300 i - 2400 j

    \texttt{Magnitude = }\sqrt{(-1300)^2+(-2400)^2}=2729.47m

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Answer:

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Explanation:

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In order to find the horizontal distance traveled by the electron you first calculate the vertical acceleration of the electron.

You use the Newton second law and the electric force on the electron:

F_e=qE=ma             (1)

q: charge of the electron = 1.6*10^-19 C

m: mass of the electron = 9.1*10-31 kg

E: magnitude of the electric field = 4.0*10^2N/C

You solve the equation (1) for a:

a=\frac{qE}{m}=\frac{(1.6*10^{-19}C)(4.0*10^2N/C)}{9.1*10^{-31}kg}=7.03*10^{13}\frac{m}{s^2}

Next, you use the following formula for the maximum horizontal distance reached by an object, with semi parabolic motion at a height of d:

x_{max}=v_o\sqrt{\frac{2d}{a}}             (2)

Here, the height d is the distance between the plates d = 2.0cm = 0.02m

vo: initial velocity of the electron = 4.0*10^6m/s

You replace the values of the parameters in the equation (2):

x_{max}=(4.0*10^6m/s)\sqrt{\frac{2(0.02m)}{7.03*10^{13}m/s^2}}\\\\x_{max}=0.095m=9.5cm

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