Answer:
Given: Vi = 382 km/h, Vf = 0 km/h, Mc = 705 kg, Md = 65 kg, Δt = 12
Required: Δx
F = Δp / Δt
= ![\frac{(Mc+Md)Vf-(Mc+Md)Vi}{t} \\\\= 6.81 * 10x^{3} N [left]\\\\x=\frac{1}{2} (Vi+Vf)\\ \\ = 637m[right]](https://tex.z-dn.net/?f=%5Cfrac%7B%28Mc%2BMd%29Vf-%28Mc%2BMd%29Vi%7D%7Bt%7D%20%5C%5C%5C%5C%3D%206.81%20%2A%2010x%5E%7B3%7D%20N%20%5Bleft%5D%5C%5C%5C%5Cx%3D%5Cfrac%7B1%7D%7B2%7D%20%28Vi%2BVf%29%5C%5C%20%5C%5C%20%3D%20637m%5Bright%5D)
Answer:
No machine is free from the effects of gravity, and even with wonderful lubrication, friction always exists. The energy a machine produces is always less than the energy put into it (energy input). ... That is why 100% efficiency in machines shall not be possible.
D if the blue car started higher it would have more energy but since the red car is lower it is going faster because it’s going down a hill
Answer: 
Explanation:
Given
Mass of the elevator is 
Time period of ascension 
cruising speed 
Distance moved by elevator during this time
Suppose Elevator starts from rest

Distance moved

Gain in Potential Energy is

Average power during this period is
