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irinina [24]
3 years ago
8

An inductor with L = 9.80 mH is connected across an ac source that has voltage amplitude 41.5 V . What value for the frequency o

f the source results in a current amplitude of 4.50 A ?
Physics
1 answer:
sashaice [31]3 years ago
7 0

Answer:

149.8Hz

Explanation:

V=I.(XL).........{1}

where (XL) is inductive reactance

(XL) =2πfL......... {2}

V= 41.5, l= 4.5, L= 9.8* 10^-³

take π to be 3.14

(XL) = V/I

= 41.5/4.5

= 9.22

f = (XL) /2πL

= 9.22* 10^³/6.28* 9.8

=149.8

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- A person is on an elevator that moves
Mademuasel [1]

Answer:

The net force acting on the person is, F = 560 N

Explanation:

Given data,

The downward acceleration of the elevator, a = 1.8 m/s²

The weight of the person is, W = mg

                                                          = 686 N

Therefore the mass of the person,

                                           m = W /g

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                                               = 70 kg

The net force acting on the person,

                                           F = mg - ma

                                               = 686 - 70 x 1.8

                                               = 560 N

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5 0
3 years ago
Two 5.0 kilogram objects have different gravitational potential energies. What property of the objects must differ?
ipn [44]

Answer:

Height.

Explanation:

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Mathematically, potential energy is given by the formula;

P.E = mgh

Where,

P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Hence, the property of the object (having a mass of 5 kilograms) which must differ to have different gravitational potential energies is the height from which they are falling from.

The object having the higher height would have a greater gravitational potential energy than the lower object.

7 0
3 years ago
a tire is rolling along a road, without slipping with a velocity v. a piece of tape is attached to the tire. When the tape is op
Kryger [21]

Answer:

The right solution will be the "2v".

Explanation:

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⇒  v_{rolling}=v_{translational}+v_{rotational}

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⇒  \omega=\frac{v_{translational}}{r}

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So that the velocity will be:

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4 0
3 years ago
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