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3 years ago

Graph each linear equation. x-y=-2

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

8 0

Answer:

the second answer

Step-by-step explanation:

start by getting the given equation into slope intercept form: y=mx+b

Just subtract x from both sides to get y by itself then divide by -1 bc y needs to be positive:

x-y=-2

-y=-x-2

y=-x/-1 -2/-1

y=x+2

This line is positive so it'll increase from left to right and also go through point (0,2) ( aka the y-intercept)

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BigorU [14]

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Step-by-step explanation:

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2 years ago

the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width

-BARSIC- [3]

Length and width of rectangle is 15 inches and 6 inches respectively

<h3><u>Solution:</u></h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

$\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}$

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

$\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}$

On solving the above expression for x we get

$\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}$

$\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}$

Hence length and width of rectangle is 15 inches and 6 inches.

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3 years ago

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steposvetlana [31]

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ArbitrLikvidat [17]

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