1) n=1 -> n=2 : delta E = -5+11 = 6. The answer is D
<span>2) n=1 -> n=3 : delta E = -2+11 = 9. The answer is B </span>
<span>3) n=1 -> n=4 : delta E = -1+11 = 10. No solution available </span>
<span>4) n=1 -> infinity delta E = 11. The answer is A </span>
<span>5) not absorbed would be C, as there is no transition with delta E of 8. </span>
Answer: 757m/s
Explanation:
Given the following :
Mole of neon gas = 1.00 mol
Temperature = 465k
Mass = 0.0202kg
Using the ideal gas equation. For calculating the average kinetic energy molecule :
0.5(mv^2) = 3/2 nRt
Where ;
M = mass, V = volume. R = gas constant(8.31 jK-1 mol-1, t = temperature in Kelvin, n = number of moles
Plugging our values
0.5(0.0202 × v^2) = 3/2 (1 × 8.31 × 465)
0.0101 v^2 = 5796.225
v^2 = 5796.225 / 0.0101
v^2 = 573883.66
v = √573883.66
v = 757.55109m/s
v = 757m/s
Answer:
just divide 22 N by 20 kg to get the acceleration in m/s2
Explanation:
I hope this is right-
Answer:
2.2 s
Explanation:
Hi!
Let's consider the origin of the coordinate system at the ground, and consider that the clam starts with zero velocity, the equation of motion of the clam is given by
![x(t) = 23.1 m - \frac{1}{2}(9.8 m/s^2) t^2](https://tex.z-dn.net/?f=x%28t%29%20%3D%2023.1%20m%20-%20%5Cfrac%7B1%7D%7B2%7D%289.8%20m%2Fs%5E2%29%20t%5E2)
We are looking for a time t for which x(t) = 0
![0 = 23.1 m - (4.9 m/s^2) t^2](https://tex.z-dn.net/?f=0%20%3D%2023.1%20m%20-%20%284.9%20m%2Fs%5E2%29%20t%5E2)
Solving for t:
![t = \sqrt{\frac{23.1}{4.9}} s = 2.17124 s](https://tex.z-dn.net/?f=t%20%3D%20%5Csqrt%7B%5Cfrac%7B23.1%7D%7B4.9%7D%7D%20s%20%3D%202.17124%20s)
Rounding at the first decimal:
t = 2.2 s
Answer: Yes.
Explanation:
Assuming Earth and Moon are isolated is space, it is possible to have a point where Earth and Moon will pull at an object with equal force.
That point will be closer to the Moon than the Earth because Moon's gravitational field strength is weaker than Earth's gravitational field strength.