Answer:
waxing gibbous is the answer.
Answer:

Explanation:
Given:
- thickness of the base of the kettle,

- radius of the base of the kettle,

- temperature of the top surface of the kettle base,

- rate of heat transfer through the kettle to boil water,

- We have the latent heat vaporization of water,

- and thermal conductivity of aluminium,

<u>So, the heat rate:</u>


<u>From the Fourier's law of conduction we have:</u>


where:
area of the surface through which conduction occurs
temperature of the bottom surface

is the temperature of the bottom of the base surface of the kettle.
When light travels from a medium with higher refractive index to a medium with lower refractive index, there is a critical angle after which all the light is reflected (so, there is no refraction).
The value of this critical angle can be derived by Snell's law, and it is equal to

where n2 is the refractive index of the second medium and n1 is the refractive index of the first medium.
In our problem, n1=1.47 and n2=1.33, so the critical angle is
<h2>
Answer: process of converting matter into energy</h2><h2>
</h2>
Nuclear fission consists of dividing a heavy nucleus into two or more lighter or smaller nuclei, by means of the bombardment with neutrons to make it unstable. In this process that takes place in the atomic nucleus, neutrons, gamma rays and <u>large amounts of energy are emitted. </u>
Then, with this division a great release of energy occurs and the emission of two or three neutrons, other particles and gamma rays.
This means fission is a process in which energy is released by the separation of the components of the nucleous of the atom.
In other words:
<h2>Matter is converted to energy .</h2>
Answer:
5.5 km
Explanation:
First, we convert the distance from km/h to m/s
910 * 1000/3600
= 252.78 m/s
Now, we use the formula v²/r = gtanθ to get our needed radius
making r the subject of the formula, we have
r = v²/gtanθ, where
r = radius of curvature needed
g = acceleration due to gravity
θ = angle of banking
r = 252.78² / (9.8 * tan 50)
r = 63897.73 / (9.8 * 1.19)
r = 63897.73 / 11.662
r = 5479 m or 5.5 km
Thus, we conclude that the minimum curvature radius needed for the turn is 5.5 km