All categories

3 years ago

How do you calculate energie

Physics

2 answers:

Taya2010 [7]3 years ago

5 0

well you can calculate energy by using

E=MC^2

E= energy

m= mass

c^2= speed of light

but it depends on the question

i hope this helped :)

lesya692 [45]3 years ago

3 0

To calculate energy, use the formula E=mc^2.

E= (kinetic) energy, m=mass, and c=speed of light (which is squared).

You might be interested in

The velocity - time graph of a ball of mass 25g moving on road is as given below:

lana [24]

Assume that the ball rolls to the right.

From the velocity-time graph, the acceleration is
a = (0 - 10 m/s)/(4 - 0 s) = -2.5 m/²

Part (a)
Because the mass of the ball is 25g or 0.025 kg, the force that the road exerts on the ball is
F = (0.025 kg)*(-2.5 m/s²) = -0.0625 N
The force is negative because it acts in opposition to the motion of the ball.

Answer: 0.0625 N to the left.

Part (b)
The direction of the force exerted by the road is to the left because it opposes the motion of the ball to the right.

Part (c)
The unit force is 1 N (Newton), with the dimension (kg-m)/s².

3 0

2 years ago

With a quick flick of her wrist, an Ultimate Frisbee player can give a Frisbee an angular velocity of 4.00 revolutions per secon

Ad libitum [116K]

Answer:

a) w = 25.1 rad/s, b) θ = 0.9599 rad , c) α = 328.1 rad/s² d) t= 0.0765 s

Explanation: Let's work on this exercise with the equations of angular kinematics

a) The angular velocity is

w = 4.00 rev / s (2π rad / 1 rev)

w = 25.1 rad/s

b) let's reduce the angle of degrees to radians

θ = 55 ° (π rad / 180 °)

θ = 0.9599 rad

c) Let's use the initial angular velocity as the system part of the rest is zero

w² = w₀² + 2 α θ

α = w² / 2 θ

α = 25.1²/2 0.9599

α = 328.1 rad / s²

w = w₀ + α t

t = w / α

t = 25.1 / 328.1

t= 0.0765 s

8 0

2 years ago

Help please :) Will award brainliest + 20pts

Neporo4naja [7]

The answer is Light rays are reflected by mirrors

5 0

2 years ago

Read 2 more answers

Two bodies, A and B, have equal kinetic energies. The mass of A is nine times that of B. The ratio of the momentum of A to that

mylen [45]

Answer:

D. 3 : 1

Explanation:

Let suppose that A and B are particles. From statement we know that $K_{A} = K_{B }$ (same kinetic energy) and $m_{A} = 9\cdot m_{B}$ . Then,

$K_{A} = K_{B}$

$\frac{1}{2}\cdot m_{A}\cdot v_{A}^{2} = \frac{1}{2}\cdot m_{B}\cdot v_{B}^{2}$

$m_{A} \cdot v_{A}^{2} = m_{B}\cdot v_{B}^{2}$

$\frac{v_{B}}{v_{A}} = \sqrt{\frac{m_{A}}{m_{B}} }$

$\frac{v_{B}}{v_{A}} = 3$

And the ratio of the momentum of A to the momentum of B is:

$r = \frac{m_{A}\cdot v_{A}}{m_{B}\cdot v_{B}}$

$r = 9\times \frac{1}{3}$

$r = 3$

Hence, the correct answer is D.

4 0

2 years ago

A person on horseback moves according to the velocity-versus-time graph shown in the figure (attached) . . A. Find the displacem

Leya [2.2K]

From my research, the following image is used for the problem. For each segment, the displacement can be obtained by looking for the area under the segment.

Part A:

displacement = (1/2)*10*2 = 10m

Part B:

displacement = [(1/2)*4*5] + (5*2) = 20m

<span>Part C:
</span>
displacement = [(1/2)*4*10] + (2*10) = 40m

4 0

2 years ago