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3 years ago

1. Find the slope of the line. 2. Find the rate of change.

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

8 0

Answer:

the slope of the line is 2 over 1 which means the answer is 2

the rate of change is c

To find the slope of the line you have to go rise over run.

to find the rate of change you have to see how much does the numbers in y go by.

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Solve this equation using substitution. {4x + y = −2} {4x + 6y = 44}

marysya [2.9K]

Answer:

4x + y = −2 --> 4x = -y - 2

4x + 6y = 44

Substitute 4x in the 2. equation.

(-y - 2) + 6y = 44

5y - 2 = 44

5y = 46

y = 9.2

4x = -9.2 - 2

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3 years ago

What is the measure of angle a in a triangle when the only other angle is 70

max2010maxim [7]

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3 years ago

Which of the following points lies on the circle whose center is at the origin and whose radius is 5?

ad-work [718]

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Equation of the circumference whose center is at $\mathsf{C(0,\,0)}$ and whose radius is $\mathsf{r=5:}$

$\mathsf{(x-x_C)^2+(y-y_C)^2=r^2}\\\\
\mathsf{(x-0)^2+(y-0)^2=5^2}\\\\
\mathsf{x^2+y^2=25}$

We are looking for the point that satisfies the equation above.

 • Testing $\mathsf{(-3,\,4):}$

$\mathsf{(-3)^2+4^2}\\\\
\mathsf{9+16}\\\\
\mathsf{25\qquad\quad\checkmark}$

The point $\mathsf{(-3,\,4)}$ lies in the circumference.

 • Testing $\mathsf{(1,\,-2):}$

$\mathsf{1^2+(-2)^2}\\\\ \mathsf{1+4}\\\\ \mathsf{5\ne 25\qquad\quad\diagup\hspace{-9}\diagdown}$

The point $\mathsf{(1,\,-2)}$ doesn't lie in the circumference.

 • Testing $\mathsf{(\sqrt{5},\,\sqrt{5}):}$

$\mathsf{(\sqrt{5})^2+(\sqrt{5})^2}\\\\ \mathsf{5+5}\\\\ \mathsf{10\ne 25\qquad\quad\diagup\hspace{-9}\diagdown}$

So, the point $\mathsf{(\sqrt{5},\,\sqrt{5})}$ doesn't lie in the circumference either.

Answer: (–3, 4).

I hope this helps. =)

8 0

4 years ago

Read 2 more answers