We will apply the Newton's second Law so the we will be able to find the acceleration.
F (tot) = ma
a = F(tot) / m
a = 32.0 N / 65.0 kg = 0.492 m/s^2
Approximately 0.492 m/s^2 is her initial acceleration if she is initially stationary and wearing steel-bladed skates.
Because no sunlight can penetrate it
The final velocity of the ball that is dropped from a height of 200m is v = 44.73 m/s .
<h3>What is velocity with example?</h3>
The rate at which an object is travelling in one direction is referred to as its velocity. an automobile traveling north on a highway, or a rocket taking off. Its velocity vector's absolute value always is equal to the motion's speed because it is a scalar.
<h3>Briefing:</h3>
Given the initial velocity of the ball (u) = 0
Distance travelled by the ball (s) = 200m
Acceleration (a) = 10 m/s²
As we know:
v² = u² + 2as
Putting values:
v² = 0+2 × (10 m/s²) × (200 m)
v = 44.73 m/s.
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The answer for the following question is explained below.
- <u><em>Therefore the work done is 130 kilo Joules.</em></u>
Explanation:
Work:
A force causing the movement or displacement of an object.
Given:
mass of the person (m) = 65 kg
height of the cliff (h) = 2000 m
To calculate:
work done (W)
We know;
According to the formula:
<u>W = m × g × h</u>
Where;
m represents mass of the person
g represents the acceleration due to gravity
where the value of g is;
<u> g = 10 m/ s²</u>
h represents the height of the cliff
From the above formula;
W = 65 × 10 × 2000
W = 130,000 J
W = 130 Kilo Joules
<u><em>Therefore the work done is 130 kilo Joules.</em></u>
