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hoa [83]
3 years ago
14

An astronaut tightens a bolt on a satellite in orbit. He rotates in a direction opposite to that of the bolt, and the satellite

rotates in the same direction as the bolt. Explain why. If a handhold is available on the satellite, can this counter-rotation be prevented
Physics
1 answer:
statuscvo [17]3 years ago
4 0

Answer: yes it can be prevented

Explanation:

The sensation of weightlessness that astronauts experience seems to make their tasks almost effortless. However, as Newton's third law of motion suggests, working in space can be physically demanding. 

As he tightens the bolt, he is rotating in the direction opposite to the bolt

It is possible if the handhold is designed in three dimensional motion where the astronaut motion will be the uplimb motion with the mass centre of hand move along circular helix trajectory

Angular momentum is conserved astronaut motion is conserved when net external torque is Zero.

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An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.50 mm. A 25
torisob [31]

Answer:

The electric field is 16666.66 V/m.

The surface charge density is 1.474\times10^{-7}\ C/m^2

The capacitance is 4.484\times10^{-12}\ F

The charge on each plate is 112.1\times10^{-12}\ C

Explanation:

Given that,

Area =7.70 cm²

Distance = 1.50 mm

Potential difference = 25.0 V

Suppose  we find the electric field between the plates, the surface charge density, the capacitance and the charge on each plates.

We need to calculate the electric field

Using formula of electric field

E=\dfrac{V}{d}

Put the value into the formula

E=\dfrac{25.0}{1.50\times10^{-3}}

E=16666.66\ V/m

We need to calculate the charge density

Using formula of charge density

\sigma=E\times\epsilon_{0}

Put the value into the formula

\sigma=16666.66\times8.85\times10^{-12}

\sigma=1.474\times10^{-7}\ C/m^2

We need to calculate the capacitance

Using formula of capacitance

C=\dfrac{\epsilon_{0}A}{d}

Put the value into the formula

C=\dfrac{8.85\times10^{-12}\times7.60\times10^{-4}}{1.50\times10^{-3}}

C=4.484\times10^{-12}\ F

We need to calculate the charge

Using formula of charge

q=CV

Put the value into the formula

q=4.484\times10^{-12}\times25.0

q=112.1\times10^{-12}\ C

Hence, The electric field is 16666.66 V/m.

The surface charge density is 1.474\times10^{-7}\ C/m^2

The capacitance is 4.484\times10^{-12}\ F

The charge on each plate is 112.1\times10^{-12}\ C

8 0
3 years ago
A particular circuit toolbox contains only 80 Ω resistors and switches, which can be open or closed. Construct a circuit, fillin
Strike441 [17]

Answer:

Here we need to make parallel connection of two 80 ohm resistors to achieve 40 ohm net resistance.

Explanation:

As we know that the resistances in series add up directly and here we are given with only the resistors of 80 Ω.

So when we connect two resistors of 80 ohm in parallel we get the resultant of 40 ohm.

Mathematically:

\frac{1}{R_p} =\frac{1}{R} +\frac{1}{R}

\frac{1}{40} =\frac{1}{R} +\frac{1}{R}

\frac{1}{40} =\frac{2}{R}

R=80\Omega gives us the only combination of two resistors in parallel.

3 0
3 years ago
What do magnets never do?<br><br><br> This is science btw.
Anika [276]

Answer:

they..don't cook foood

8 0
2 years ago
1. Set frequency of wave generator to 5Hz.
ivann1987 [24]

Separate the barriers so they have a 2cm gap between them.

3 0
3 years ago
A 1.15 kg book is at rest on the table. What is the magnitude of the normal force that the table is exerting on the book?
Agata [3.3K]

Answer:

11.27N

Explanation:

Given parameters:

Mass of the book  = 1.15kg

Unknown:

Magnitude of the normal force  = ?

Solution:

The normal force is the vertical force exerted by a body on an object.

It can be described as the weight of an object.

 Normal force  = mass x acceleration due to gravity

 Normal force  = 1.15 x 9.8  = 11.27N

5 0
2 years ago
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