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Nikitich [7]
2 years ago
7

: In heavy rushIn heavy rush-hour traffic you drive in a straight line at 12 m/s for 1.5 minutes, then you have to stop for 3.5

minutes, and finally you drive at 15 m/s for another 2.5 minutes.
Physics
1 answer:
zhuklara [117]2 years ago
8 0
Guessing you want the average speed. We can multiple each speed by the time we spent going that speed, and them all together and then divide by the total time we spent in traffic to get the average speed. We spent a total of 7.5 minutes in traffic, so average speed  = (12*1.5+0*3.5+15*2.5)/7.5 = 7.4 m/s
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When Bob needs to send Alice a message with a digital signature, whose private key is used to encrypt the hash?
nadya68 [22]

Answer: Bob's private key

Explanation:

Since Bob is sending Alice the message, it simply implies he must have encrypted it with his key that Alice can be able to use to decrypt the message.

3 0
2 years ago
An empty container has a mass of 3 g. When it is filled with 5 cm3 of a liquid,
IrinaK [193]

Answer:

THE MASS OF THE LIQUID IS 22.5 g

Explanation:

Density = 0.180 g/cm3

Side length = 5 cm

Mass = unknown

To calculate the mass of the liquid, we use the formula:

Mass = density * volume

Volume of a cube or cuboid container = l^3

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So therefore, the mass of the liquid is:

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3 0
3 years ago
A thin rod (length = 2.97 m) is oriented vertically, with its bottom end attached to the floor by means of a frictionless hinge.
nlexa [21]

Answer:

a)  w = 2.57 rad / s , b)   α = 3.3 rad / s²

Explanation:

a) Let's use the conservation of mechanical energy, we will write it in two points the highest and when touching the ground

Initial. Higher

       Em₀ = U = m g h

Final. Touching the ground

       Em_{f} = K = ½ I w²

How energy is conserved

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       mg h = ½ I w2

The moment of specific object inertia

        I = m L²

We replace

       m g h = ½ (mL²) w²

       w² = 2g h / L²

The height of the object is the length of the bar

        h = L

        w = √ 2g / L

       w = √ (2 9.8 / 2.97)

       w = 2.57 rad / s

b) the angular acceleration can be found from Newton's second rotational law

       τ = I α

       W L = I α

       mg L = (m L²) α

       α = g / L

       α = 9.8 / 2.97

       α = 3.3 rad / s²

3 0
3 years ago
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