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Nikitich [7]
3 years ago
7

: In heavy rushIn heavy rush-hour traffic you drive in a straight line at 12 m/s for 1.5 minutes, then you have to stop for 3.5

minutes, and finally you drive at 15 m/s for another 2.5 minutes.
Physics
1 answer:
zhuklara [117]3 years ago
8 0
Guessing you want the average speed. We can multiple each speed by the time we spent going that speed, and them all together and then divide by the total time we spent in traffic to get the average speed. We spent a total of 7.5 minutes in traffic, so average speed  = (12*1.5+0*3.5+15*2.5)/7.5 = 7.4 m/s
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Well a basic explanation is that some elements have enough electrons to be considered stable. These elements do not need to react with other elements to gain more electrons. Reactive elements are no where near stable; they respond with other elements in order to become stable. The more unstable, the harsher the reaction is.

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Answer:

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Consider a concave mirror that has a focal length f. In terms of f, determine the object distances that will produce a magnifica
Aleks04 [339]

We have that the magnification of each focal length is given respectively as

A) has u=3\frac{f}{2}

B) has u=4\frac{f}{3}

C) has  u=5\frac{f}{4}

From the question we are told that:

Focal Length F

Generally, the equation for Magnification is mathematically given by

M=\frac{-v}{u}

Therefore

v=2u

For A

M=-2

Therefore

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

\frac{1}{f}=\frac{1}{u}+\frac{1}{2u}

Therefore

u=3\frac{f}{2}

For B

M=-3

Therefore

v=3u

Where

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

\frac{1}{f}=\frac{1}{u}+\frac{1}{3u}

Therefore

u=4\frac{f}{3}

For C

M=-4

Therefore

v=4u

Therefore

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

\frac{1}{f}=\frac{1}{u}+\frac{1}{4u}

Therefore

u=5\frac{f}{4}

Conclusion

From the calculations above we can rightly say that the magnifications of the values above are

A has u=3\frac{f}{2}

B has u=4\frac{f}{3}

C has  u=5\frac{f}{4}

For more information on this visit

brainly.com/question/14468351

3 0
2 years ago
The blue gill is a type of fish that lives in Indiana ponds. It's diet consists of insects snails other small fish and fish eggs
laiz [17]

Answer:

Bluegills are the primary food source in every farm pond. They spawn from May to September and provide a large amount of food to the predators in the pond.

Explanation:

6 0
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