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xxTIMURxx [149]
3 years ago
10

The __is (are) an example of a transform boundary.

Chemistry
1 answer:
Natalija [7]3 years ago
7 0

Answer:

The San Andreas Fault in California is an example of a transform boundary.

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If you travel through a city and find that you travel 5 km in 30 minutes, you could say that your constant speed is 6 km/h. is i
Reika [66]

Answer:

False.

Explanation:

(5 kilometers / 30 minutes), you could then say that in 60 minutes (one hour) you would be traveling at (10 kilometers / 60 minutes)...

Therefore, it is unlikely that you would be traveling at (6 kilometers / hour), so the answer should be... False.

7 0
3 years ago
Assume that all of this fossil fuel is in the form of octane (C8H18) and calculate how much CO2 in kilograms is produced by worl
AnnZ [28]

The given question is incomplete. the complete question is:

The world burns the fossil fuel equivalent of approximately 9.50\times 10^{12} kg of petroleum per year. Assume that all of this petroleum is in the form of octane. Calculate how much CO2 in kilograms is produced by world fossil fuel combustion per year.( Hint: Begin by writing a balanced equation for the combustion of octane.)

Answer: 29\times 10^{12}kg

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

2_C8H_{18}+17O_2\rightarrow 16CO_2+18H_2O

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of octane}=\frac{9.50\times 10^{12}\times 10^3g}{114g/mol}=0.083\times 10^{15}moles

According to stoichiometry :

As 2 moles of octane give = 16 moles of CO_2

Thus 0.083\times 10^{15}moles of octane give =\frac{16}{2}\times 0.083\times 10^{15}=0.664\times 10^{15}moles  of CO_2

Mass of CO_2=moles\times {\text {Molar mass}}=0.664\times 10^{15}moles\times 44g/mol=29.2\times 10^{15}g=29.2\times 10^{12}kg

Thus 29\times 10^{12}kg of CO_2 is produced by world fossil fuel combustion per year.

5 0
3 years ago
What are the molecular formula of 20 elements​
baherus [9]

Explanation:

Hydrogen (H)

Helium (He)

Lithium (Li)

Beryllium (Be)

Boron (B)

Carbon (C)

Nitrogen (N)

Oxygen (O)

Fluorine (F)

Neon (Ne)

Sodium (Na)

Magnesium (Mg)

Aluminum (Al)

Silicon (Si)

Phosphorus (P)

Sulfur (S)

Chlorine (Cl)

Argon (Ar)

Potassium (K)

Calcium (Ca)

Hope this is correct and helpful

HAVE A GOOD DAY!

3 0
3 years ago
If you have 12.5g of fluoride and 16.2g of sodium, which is the limiting reactant and how sodium fluoride in grams is your theor
Korvikt [17]

Answer:

F2 is the limiting reactant

27.6 grams of NaF is produced.

Explanation:

Balance the equation first.

2Na+ F2 ---> 2NaF

To find the limiting reactant, solve for how much NaF can be produced with Na and F2

12.5g F2 x (1 mole F2/ 38.00 grams F2)x (2 mole NaF/ 1 mole F2)

=0.658 moles NaF

16.2g Na x (1 mole Na/ 22.99 grams Na)x (2 mole NaF/ 2 mole Na)

=0.705 moles NaF

Since F2 produced the least NaF, F2 is the limiting reactant.

Now, to find how much NaF there is, use the moles solved above with F2 as the limiting reactant.

0.658 moles NaF x (41.99 grams NaF/ 1 mole NaF)= 27.6 moles NaF

27.6 moles of NaF would be theoretically produced.

8 0
3 years ago
This type of pure substance contains more than one type of element chemically bonded
Alex787 [66]

Answer:

A. Compounds

Explanation:

Firstly, don't let the word "pure" confuse you; this is pretty much irrelevant to the question.

The key to answering this question lies in "substance" and "more than one type of element chemically bonded."

Something you ought to memorize is that a substance is either an element or compound. Therefore, you can eliminate choices B./C.

Next, use the part of the definition that says "more than one type of element chemically bonded" to conclude that it's a compound. Not only is this the definition of a compound, but the fact that is says <em>more than one type of element</em> should automatically tell you that it is different from just a regular element (Choice D.).

6 0
3 years ago
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