Draw the structures of the products of the neutralization reaction between amide ion (nh2-) and acetic acid.
1 answer:
The reaction between strong acid and strong base which results in the formation of salt and water is said to be a neutralization reaction.
The given acid and base are acetic acid and amide ion. Since, acetic acid is a weak acid and amide ion is strong base.
The amide ion is a strong base so it will extract the proton from acetic acid and results in the formation of ammonia and acetate ion.
The reaction will takes place as shown in the image.
You might be interested in
This problem is providing the basic dissociation constant of ibuprofen (IB) as 5.20, its pH as 8.20 and is requiring the equilibrium concentration of the aforementioned drug by giving the chemical equation at equilibrium it takes place. The obtained result turned out to be D) 4.0 × 10−7 M, according to the following work:
First of all, we set up an equilibrium expression for the given chemical equation at equilibrium, in which water is omitted for it is liquid and just aqueous species are allowed to be included:
Next, we calculate the concentration of hydroxide ions and the Kb due to the fact that both the pH and pKb were given:
Then, since the concentration of these ions equal that of the conjugated acid of the ibuprofen (IBH⁺), we can plug in these and the Kb to obtain:
Finally, we solve for the equilibrium concentration of ibuprofen:
Learn more:
(Weak base equilibrium calculation) brainly.com/question/9426156