Draw the structures of the products of the neutralization reaction between amide ion (nh2-) and acetic acid.
1 answer:
The reaction between strong acid and strong base which results in the formation of salt and water is said to be a neutralization reaction.
The given acid and base are acetic acid and amide ion. Since, acetic acid is a weak acid and amide ion is strong base.
The amide ion is a strong base so it will extract the proton from acetic acid and results in the formation of ammonia and acetate ion.
The reaction will takes place as shown in the image.
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<u>Answer:</u> The mass of nickel (II) oxide and aluminium that must be used is 18.8 g and 4.54 g respectively.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For nickel:</u>
Given mass of nickel = 14.8 g
Molar mass of nickel = 58.7 g/mol
Putting values in equation 1, we get:
For the given chemical reaction:
- <u>For nickel (II) oxide:</u>
By Stoichiometry of the reaction:
3 moles of nickel are produced from 3 moles of nickel (II) oxide
So, 0.252 moles of nickel will be produced from of nickel (II) oxide
Now, calculating the mass of nickel (II) oxide by using equation 1:
Molar mass of nickel (II) oxide = 74.7 g/mol
Moles of nickel (II) oxide = 0.252 moles
Putting values in equation 1, we get:
- <u>For aluminium:</u>
By Stoichiometry of the reaction:
3 moles of nickel are produced from 2 moles of aluminium
So, 0.252 moles of nickel will be produced from of aluminium
Now, calculating the mass of aluminium by using equation 1:
Molar mass of aluminium = 27 g/mol
Moles of aluminium = 0.168 moles
Putting values in equation 1, we get:
Hence, the mass of nickel (II) oxide and aluminium that must be used is 18.8 g and 4.54 g respectively.