The net force on the object as described is; 58.84N
Two forces acting on the object are;
- The <em>applied force and the frictional force.</em>
In essence; the frictional force can be evaluated as;
- Frictional force; = coefficient × Weight of object.
- Frictional force = 0.21 × 20 × 9.8.
- Frictional force = 41.16N
- The Net force = Applied force - frictional force
Net Force = 58.84 N.
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Answer:
Your kinetic energy is 631800 J
Explanation:
Well i hope this helps
Yo I wish I was at higheschool and I think the last one is darker or the same cause of the reflection
Kinetic energy = (1/2) (mass) (speed)²
Since the 'speed' in the KE formula is squared, if the car's speed
increases by 5 times, its kinetic energy increases by (5²) = 25 times.
The loss of kinetic energy in a skid is just the wo0rk done by friction
between the tires and pavement. So the skid distance is proportional
to the initial kinetic energy, and the car must skid 25 times as far when
it enters the skid at the higher speed.
25 x 30m = 750 meters